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SVEN [57.7K]
3 years ago
12

What is the area of the logo?​

Mathematics
2 answers:
Ludmilka [50]3 years ago
4 0

Answer:

the \: area \: of \: the \: logo \: is \:  {91cm}^{2}

Step-by-step explanation:

To determine the area of the logo you have to calculate the area of the triangle and the square that comform it and then add the four areas.

Area of the square.

To calculate the area of the square you have to calculate the square of one of its sides, following the formula:

a =  {a}^{2}

Where "a" is the length of one of its side.

The side length of the square is a=7cm, so its area will be:

asquare =  {7}^{2}  \\ asquare =  {49cm}^{2}

Area of the triangles.

The three triangles are equal, they have a base equal to the side of the square, i.e. with a length of 7cm, and their height is h=4cm.

To calculate the area of one triangle, you have to multiply its base by its height and divide by 2, following the formula:

a =  \frac{b.h}{2}  \\  a =  \frac{7.4}{2}  \\ a =  \frac{28}{2}  \\ a =  {14cm}^{2}

The area calculated the correspond to one triangle, since all triangles are congruent, you have to multiply the said area by 3 to determine the area of three figures:

atriangles = 3a \\ atriangles =  {42cm}^{2}

Now that the area of all shape are calculated, you have to add them to determine the area of the logo:

alogo = asquare + atriangle \\ alogo = 49 + 42 \\ alogo =  {91cm}^{2}

AlekseyPX3 years ago
3 0

Answer:

(7×7)+3(1/2×7×4)

49+42

91cm²

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The mean annual cost of an automotive insurance policy is normally distributed with a mean of $1140 and standard deviation of $3
DerKrebs [107]

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c) 0.8485 = 84.85%.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

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The parameters in this problem are given as follows:

\mu = 1140, \sigma = 310, n = 16, s = \frac{310}{\sqrt{16}} = 77.5

Item a:

The probability is the <u>p-value of Z when X = 1250 subtracted by the p-value of Z when X = 1000</u>, hence:

X = 1250:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

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Z = 1.42

Z = 1.42 has a p-value of 0.9222.

X = 1000:

Z = \frac{X - \mu}{s}

Z = \frac{1000 - 1140}{77.5}

Z = -1.81

Z = -1.81 has a p-value of 0.0351.

0.9222 - 0.0351 = 0.8871 = 88.71% probability.

Item b:

The probability is <u>one subtracted by the p-value of Z when X = 1250</u>, hence:

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Item c:

The probability is the <u>p-value of Z when X = 1220</u>, hence:

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Z = \frac{1220 - 1140}{77.5}

Z = 1.03

Z = 1.03 has a p-value of 0.8485.

0.8485 = 84.85% probability.

More can be learned about the normal distribution at brainly.com/question/4079902

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