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SVEN [57.7K]
3 years ago
12

What is the area of the logo?​

Mathematics
2 answers:
Ludmilka [50]3 years ago
4 0

Answer:

the \: area \: of \: the \: logo \: is \:  {91cm}^{2}

Step-by-step explanation:

To determine the area of the logo you have to calculate the area of the triangle and the square that comform it and then add the four areas.

Area of the square.

To calculate the area of the square you have to calculate the square of one of its sides, following the formula:

a =  {a}^{2}

Where "a" is the length of one of its side.

The side length of the square is a=7cm, so its area will be:

asquare =  {7}^{2}  \\ asquare =  {49cm}^{2}

Area of the triangles.

The three triangles are equal, they have a base equal to the side of the square, i.e. with a length of 7cm, and their height is h=4cm.

To calculate the area of one triangle, you have to multiply its base by its height and divide by 2, following the formula:

a =  \frac{b.h}{2}  \\  a =  \frac{7.4}{2}  \\ a =  \frac{28}{2}  \\ a =  {14cm}^{2}

The area calculated the correspond to one triangle, since all triangles are congruent, you have to multiply the said area by 3 to determine the area of three figures:

atriangles = 3a \\ atriangles =  {42cm}^{2}

Now that the area of all shape are calculated, you have to add them to determine the area of the logo:

alogo = asquare + atriangle \\ alogo = 49 + 42 \\ alogo =  {91cm}^{2}

AlekseyPX3 years ago
3 0

Answer:

(7×7)+3(1/2×7×4)

49+42

91cm²

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If you have a demand function of Qd=48-9P and a supply function of Qs=-12+6P,
jenyasd209 [6]

Answer:

The equilibrium quantity is 26.4

Step-by-step explanation:

Given

Q_d = 48 - 9P

Q_s = 12 + 6P

Required

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First, we need to determine the equilibrium by equating Qd to Qs

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Q_d = Q_s

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3 years ago
A researcher is going to estimate the average typing speed of students of a college. He selects a random sample of 20 students a
Stella [2.4K]

Answer:

The margin of error of the 90% confidence interval of a student's average typing speed is of 1.933 wpm.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

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M = T\frac{s}{\sqrt{n}}

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M = T\frac{s}{\sqrt{n}}

M = 1.7291\frac{5}{\sqrt{20}}

M = 1.933

The margin of error of the 90% confidence interval of a student's average typing speed is of 1.933 wpm.

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