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2 years ago

The width of a rectangular card is 2 cm lekss than the Tength. The area is 15 cm. Find the length and

Mathematics

1 answer:

Yuri [45]2 years ago

5 0

Answer:

Step-by-step explanation:

Area A = 15square cm

Length L = x

Width w = x - 2

Area = L × w

15 = x(x - 2)

15 = x^2 -2x

x^2 -2x - 15 = 0

Solving by factorization

x^2 - 5x + 3x - 15 = 0

(x^2 -5x) + (3x -15) = 0

x(x - 5) + 3(x - 5) = 0

(x + 3)(x - 5) = 0

(x + 3) = 0 or (x - 5) = 0

x = -3 or 5

Since x can't be negative therefore x is 5cm

Length = 5cm

Width = 5-2 = 3cm

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2 years ago

What is the circumference of the circle? (use 3.14 for pi) r = 50mm

Alexxandr [17]

Answer:

Step-by-step explanation:

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2 years ago

Can someone help me with this? PLs i'm so confused!

barxatty [35]

1. E. $sine\ A = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{5}{13}$

2. L. $cos\ A = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{12}{13}$

3. $tan\ A = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{5}{12}$

4. Y. $sin\ B = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{5}{13}$

5. W. $cos\ B = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{12}{13}$

6. $tan\ B = \frac{b}{a} = \frac{adjacent}{opposite} = \frac{AC}{BC} = \frac{12}{5} = 2\frac{2}{5}$

7. $sin\ A = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{1}{2}$

8. W. $cos\ A = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{\sqrt{3}}{2}$

9. I. $tan\ A = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{1}{\sqrt{3}} = \frac{1}{\sqrt{3}} * \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{3}}{3}$

10. $sin\ B = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{1}{2}$

11. E. $cos\ B = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{\sqrt{3}}{1} = \sqrt{3}$

12. I. $tan\ B = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{1}{\sqrt{3}} = \frac{1}{\sqrt{3}} * \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{3}}{3}$

13. U. $sin\ A = \frac{a}{c} = \frac{hypotenuse}{opposite} = \frac{BC}{AB} = \frac{12}{15} = \frac{4}{5}$

14. I. $cos\A = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{9}{15} = \frac{3}{5}$

15. $tan\ A = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{12}{9} = \frac{4}{3} = 1\frac{1}{3}$

16. R. $sin\ B = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{4}{\sqrt{65}} = \frac{4}{\sqrt{65}} * \frac{\sqrt{65}}{\sqrt{65}} = \frac{4\sqrt{65}}{65}$

17. M. $cos\ B = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{7}{4} = 1\frac{3}{4}$

18. N. $tan\ B = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{4}{7}$

19. L. $sin\ A = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{16}{34} = \frac{8}{17}$

20. H. $cos\ B = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \fac{AC}{AB} = \frac{30}{34} = \frac{15}{17}$

21. $tan\ B = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{16}{30} = \frac{8}{15}$

22. O. $sin\ A = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{1}{\sqrt{2}} = \frac{1}{\sqrt{2}} * \frac{\sqrt{2}}{\sqrt{2}} = \frac{\sqrt{2}}{2}$

23. O. $cos\ A = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{1}{\sqrt{2}} = \frac{1}{\sqrt{2}} * \frac{\sqrt{2}}{\sqrt{2}} = \frac{\sqrt{2}}{2}$

24. N. $tan\ A = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{1}{1} = 1$

7 0

3 years ago

Compute the fare without tip: 1 passenger, 9.5 miles. Round to nearest fifth of a mile when dividing.

vladimir1956 [14]

The fare without tip for the Metro Taxi is of 1 passenger and 9.5 miles is $27.83.

The given parameters:

Number of passenger = 1
Total distance = 9.5 miles
Cost of first 0.2 mile = $0.75
Cost of additional mile = $0.55
Cost of a passenger = $1.50

The fare without tip for the Metro Taxi is calculated as follows;

for the first 0.2 mile = $0.75
the remaining distance = 9.5 - 0.2 = 9.3 miles

$cost \ of \ distance = \$ 0.75 \ \ + \ \ \frac{\$ 0.55}{0.2 \ mile} \times 9.3 \ miles\\\\cost \ of \ distance = \$ 26.325$

Cost of 1 passenger = $1.50

The total cost is calculated as follows;

total cost = $1.50 + $26.325

total cost = $27.83

Thus, the fare without tip for the Metro Taxi is of 1 passenger and 9.5 miles is $27.83.

The complete question is below:

Compute the fare without tip: 1 passenger, 9.5 miles. Round to nearest fifth of a mile when dividing.

Metro Taxi: first 1/5 mi= $0.75, each additional 1/5 mi= $0.55, each additional passenger= $1.50.

Learn more about cost per miles here: brainly.com/question/2513267

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2 years ago

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Mice21 [21]

Answer:

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Step-by-step explanation:

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4 0

2 years ago

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