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3 years ago

The width of a rectangular card is 2 cm lekss than the Tength. The area is 15 cm. Find the length and

Mathematics

1 answer:

Yuri [45]3 years ago

5 0

Answer:

Step-by-step explanation:

Area A = 15square cm

Length L = x

Width w = x - 2

Area = L × w

15 = x(x - 2)

15 = x^2 -2x

x^2 -2x - 15 = 0

Solving by factorization

x^2 - 5x + 3x - 15 = 0

(x^2 -5x) + (3x -15) = 0

x(x - 5) + 3(x - 5) = 0

(x + 3)(x - 5) = 0

(x + 3) = 0 or (x - 5) = 0

x = -3 or 5

Since x can't be negative therefore x is 5cm

Length = 5cm

Width = 5-2 = 3cm

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195 minutes

Step-by-step explanation:

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3 years ago

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Gnesinka [82]

Answer:

r = √3v/π

Step-by-step explanation:

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4 years ago

What transformations are needed to change the parent cosine function to y=3cos(10(x-pi))?

LUCKY_DIMON [66]

Answer:

The graph of $y=cos(x)$ is:

*Stretched vertically by a factor of 3

*Compressed horizontally by a factor $\frac{1}{10}$ .

*Moves horizontally $\pi$ units to the rigth

The transformation is:

$y=3f(10(x-\pi))$

Step-by-step explanation:

If the function $y=cf(h(x+b))$ represents the transformations made to the graph of $y= f(x)$ then, by definition:

If $0$ then the graph is compressed vertically by a factor c.

If $|c| > 1$ then the graph is stretched vertically by a factor c

If $c$ then the graph is reflected on the x axis.

If $b> 0$ The graph moves horizontally b units to the left

If $b$ The graph moves horizontally b units to the rigth

If $0$ the graph is stretched horizontally by a factor $\frac{1}{h}$

If $h> 1$ the graph is compressed horizontally by a factor $\frac{1}{h}$

In this problem we have the function $y=3cos(10(x-pi))$ and our parent function is $y = cos(x)$

The transformation is:

$y=3f(10(x-\pi))$

Then $c =3>1$ and $b =-\pi < 0$ and $h=10 > 1$

Therefore the graph of $y=cos(x)$ is:

Stretched vertically by a factor of 3.

Also as $h=10$ the graph is compressed horizontally by a factor $\frac{1}{10}$ .

Also, as $b =-\pi < 0$ The graph moves horizontally $\pi$ units to the rigth

6 0

3 years ago

Suppose that an individual has a body fat percentage of 12.1% and weighs 139 pounds. How many pounds of his weight is made up of

ArbitrLikvidat [17]

Answer:

16.8 pounds

Step-by-step explanation:

Given the following :

Body fat percentage = 12.1%

Weight = 139 pounds

How may pounds of the person's weight is made up of fat:

That is 12.1% of the person's entire body weight

Pound of person's weight composed of fat:

12.1% of 139

(12.1 / 100) × 139

0.121 × 139

= 16.819 pounds.

= 16.8 pounds

3 0

3 years ago