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2 years ago

What is the answer? for this question

Mathematics

1 answer:

nirvana33 [79]2 years ago

7 0

Answer:

Step-by-step explanation:

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3 years ago

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3 years ago

(a) Find a 90% confidence interval for the population mean price (per 100 pounds) that farmers in this region get for their wate

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Answer:

The margin of error (E) $=0.49$

Step-by-step explanation:

Given,

mean $\bar{x}=6.88$

standard deviation $\sigma=1.90$

sample size $n=41$

$90\% \quad \text{confidence interval}$

Critical value $=\frac{z_\alpha}{2}\quad \quad\quad[\because\;\alpha=1-\text{confidence interval}]$

$=1-0.90$

$\Rightarrow \alpha=0.1$

Critical value $=\frac{z_{0.1}}{2}$

$=z_{0.05}$

$=1.645$

The margin of error (E) $=\frac{z_\alpha}{2} \times\frac{\sigma}{\sqrt{n} }$

$=1.645\times\frac{1.90}{\sqrt{41} }$

$=0.49$

Hence, The margin of error (E) $=0.49$

Complete question is attached in below.

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3 years ago

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2 years ago

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