That would be option A
because square root of 81 is 9 and square root m^6 is m^3.
Answer:
77.64% probability that there will be 0 or 1 defects in a sample of 6.
Step-by-step explanation:
For each item, there are only two possible outcomes. Either it is defective, or it is not. The probability of an item being defective is independent of other items. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
The true proportion of defects is 0.15
This means that 
Sample of 6:
This means that 
What is the probability that there will be 0 or 1 defects in a sample of 6?

In which




77.64% probability that there will be 0 or 1 defects in a sample of 6.
Answer:
C)
Step-by-step explanation:
if the shapes were rotated it would be easier to prove that the shape are congruent. Hope this helps :)
Answer:
A. =4x3+9x2−25x+12
Step-by-step explanation:
(x+4)(4x−3)(x−1)
=((x+4)(4x−3))(x+−1)
=((x+4)(4x−3))(x)+((x+4)(4x−3))(−1)
=4x3+13x2−12x−4x2−13x+12
=4x3+9x2−25x+12
Answer:
The frequency distribution is given below:
Class Frequency
0 - 9 9
10 - 19 6
20 - 29 3
30 - 39 3
40 - 49 3
From the given 4 options, the histogram in option A accurately displays this data. Hence the option A is correct.