Taking into account the reaction stoichiometry, 1 mole of silver chromate Ag₂CrO₄ are produced in this reaction.
<h3>Reaction stoichiometry</h3>
In first place, the balanced reaction is:
2 AgC₂H₃O₂ + K₂CrO₄ → Ag₂CrO₄ + 2 KC₂H₃O₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- AgC₂H₃O₂: 2 moles
- K₂CrO₄: 1 mole
- Ag₂CrO₄: 1 mole
- KC₂H₃O₂: 2 moles
<h3>Moles of Ag₂CrO₄ formed</h3>
By reaction stoichiometry 2 moles of AgC₂H₃O₂ form 1 mole of Ag₂CrO₄.
In other words, according to this balanced chemical equation, 1 mole of silver chromate Ag₂CrO₄ are produced in this reaction.
Learn more about the reaction stoichiometry:
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Answer:
For the Ag ground-state ion, the type of orbital from which an electron will need to be removed to form the ion of greater positive charge is :
<u>s-orbital</u>
Explanation:
Naming of orbitals :
s = s-orbital
p = p-orbital
d = d-orbital
The electronic configuration of Ag is :
![[Kr]4d^{10}5s^{1}](https://tex.z-dn.net/?f=%5BKr%5D4d%5E%7B10%7D5s%5E%7B1%7D)
The Outermost shell = 5s
so electron should be removed from 5s . there is only 1 electron in 5s -shell. Hence , Ag exist +1 oxidation state.
According to Aufbau's Rule : Electron will be filled first in lower energy orbital.
The electron should be removed first ,from the higher energy orbital.This is because high energy orbitals are away from the nucleus and can be easily removed. The outermost electron feel less attraction of the nucleus
Ionization energy : Energy required to remove the electron from the outermost shell of the element in the gaseous state.
![Ag\rightarrow Ag^{+} +e^{-}](https://tex.z-dn.net/?f=Ag%5Crightarrow%20Ag%5E%7B%2B%7D%20%2Be%5E%7B-%7D)
Hence it will form Ag+ cation
<u>Ag+:</u>
![[Kr]4d^{10}](https://tex.z-dn.net/?f=%5BKr%5D4d%5E%7B10%7D)
Outer shell is removed after loss of electron.
Answer:
The rate of reaction will maintain constant
Explanation:
Rate of reaction is proportionate to rate constant x [A] ^2 x [B]. This means that the order of reaction with respect to C is 0 as it does not affect the rate of reaction as seen in the rate equation.
Essentially, order of reaction with respect to C is [C] ^0
Hence if [C] triples and becomes [3C]^0, the result will still be 1 as anything to the power of 0 is 1.
Therefore, the answer is that the rate of reaction will remain constant.
Explanation:
hope the picture above help u understand:)
Answer: Rougher surfaces have more friction between them than smoother surfaces. That's why we put sand on icy sidewalks and roads. You can't slide as far across ice with shoes as you can on the blades of skates. The rougher surface of the soles of the shoes causes more friction and slows you down.<em> There are four types of friction: static, sliding, rolling, and fluid friction. Static, sliding, and rolling friction occur between solid surfaces. Static friction is strongest, followed by sliding friction, and then rolling friction, which is weakest.</em>
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