PLEASE HELP MEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE

Write equation to represent the Hydrogenation reactions

garik1379 [7]

Explanation:

vegetable oils have long unsaturated carbon chains which can converted into vegetable ghee

4 0

3 years ago

What is the threshold frequency ν0 of cesium?

Montano1993 [528]

I think this is what you're after:

Cs(g) → Cs^+ + e⁻ ΔHIP = 375.7 kJ mol^-1 [1]

Convert to J and divide by the Avogadro Const to give E in J per photon

E = 375700/6.022×10^23 = 6.239×10^-19 J

Plank relationship E = h×ν E in J ν = frequency (Hz s-1)

Planck constant h = 6.626×10^-34 J s

6.239×10^-19 = (6.626×10^-34)ν

ν = 9.42×10^14 s^-1 (Hz)

IP are usually given in ev Cs 3.894 eV

E = 3.894×1.60×10^-19 = 6.230×10^-19 J per photon

4 0

3 years ago

in your notebook,write the appropriate tempo for the following actions.Then demostrate the actions then,demostrate the action in

pogonyaev

Answer:

cell :—

•They lack a well-defined nucleus, have a nucleoid instead.

•Usually have double-stranded, circular DNA.

•Do not have mitochondria.

Eukaryotic cell :—

•Have a well-defined nucleus enclosed in the nuclear membrane.

•Have a linear double-stranded nucleus.

•Mitochondria are present.

6 0

3 years ago

How do you find the molecular formula from the empirical formula?

miskamm [114]

To find them you would have numbers of the elements in percentage or grams then you divide them by their molar mass to get their moles. From there you divide by the smallest number. Round it to two or one sig fig. If you have a number that is for ex. 2.5 you multiply it by 2 to make it whole as well the other whole numbers. Then to find the molecular formula the problem must give you another molar mass and using your empirical formula convert it to its molar mass then you divide them, larger number over smaller number. You should get a number round it to 1 sig fig. Now you use that number and multiply the subscripts on the empirical formula to get the molecular formula.

7 0

3 years ago

Anything in red is the question

laila [671]

Answer:

Question 19: the three are molecular compounds.

Question 20: CuSO₄.5H₂O

Explanation:

Question 19.

C₂H₄

HF

H₂O₂

All of them are the combination of two kinds of different atoms in fixed proportions.

C₂H₄: two carbon atoms per four hydrogen atoms

HF: one hydrogen atom per one fluorine atom

H₂O₂: two hydrogen atoms per two oxygent atoms

Thus, they all meet the definition of compund: a pure substance formed by two or more different elements with a definite composition.

Molecular compounds are formed by covalent bonds and ionic compounds are formed by ionic bonds.

Two non-metal elements, like H-F, C - C, C - H, H-O, H - H, and O - O will share electrons forming covalent bonds to complete their valence shell. Thus, the three compounds are molecular and not ionic.

Question 20. Formula of copper(II) sulfate hydrate with 36.0% water.

Copper(II) sulfate is CuSO₄. Its molar mass is 159.609g/mol

Water is H₂O. Its molar mass is 18.015g/mol

Calling x the number of water molecules in the hydrate, the percentage of water is:

$\dfrac{18.015x}{18.015x+159.609}=36\%\\ \\ \\ \dfrac{18.015x}{18.015x+159.609}=0.36$

From which we can solve for x:

$18.015x=6.4854x+57.45924\\ \\ 11.5296x=57.45924\\ \\ x\approx4.98\approx5$

Thus, there are 5 molecules of water per each unit of CuSO₄, and the formula is:

CuSO₄.5H₂O

4 0

3 years ago