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elena-14-01-66 [18.8K]
3 years ago
13

Factor 3x2 - 15x - 42.

Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
8 0
3 x^{2} - 15x - 42
(x-7)(x+2)
 x-7=0 x+2=0
 x=7,-2
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Find the roots of f(x)=2x^2+7x+3 by using the quadratic formula
Oksana_A [137]

Answer:

f(x) = 2 ( x + 7/4)2  - 25/8

Step-by-step explanation:

4 0
2 years ago
The probability density function of the time to failure of an electronic component in a copier (in hours) is f(x) for Determine
salantis [7]

The question is incomplete. Here is the complete question.

The probability density function of the time to failure of an electronic component in a copier (in hours) is

                                              f(x)=\frac{e^{\frac{-x}{1000} }}{1000}

for x > 0. Determine the probability that

a. A component lasts more than 3000 hours before failure.

b. A componenet fails in the interval from 1000 to 2000 hours.

c. A component fails before 1000 hours.

d. Determine the number of hours at which 10% of all components have failed.

Answer: a. P(x>3000) = 0.5

              b. P(1000<x<2000) = 0.2325

              c. P(x<1000) = 0.6321

              d. 105.4 hours

Step-by-step explanation: <em>Probability Density Function</em> is a function defining the probability of an outcome for a discrete random variable and is mathematically defined as the derivative of the distribution function.

So, probability function is given by:

P(a<x<b) = \int\limits^b_a {P(x)} \, dx

Then, for the electronic component, probability will be:

P(a<x<b) = \int\limits^b_a {\frac{e^{\frac{-x}{1000} }}{1000} } \, dx

P(a<x<b) = \frac{1000}{1000}.e^{\frac{-x}{1000} }

P(a<x<b) = e^{\frac{-b}{1000} }-e^\frac{-a}{1000}

a. For a component to last more than 3000 hours:

P(3000<x<∞) = e^{\frac{-3000}{1000} }-e^\frac{-a}{1000}

Exponential equation to the infinity tends to zero, so:

P(3000<x<∞) = e^{-3}

P(3000<x<∞) = 0.05

There is a probability of 5% of a component to last more than 3000 hours.

b. Probability between 1000 and 2000 hours:

P(1000<x<2000) = e^{\frac{-2000}{1000} }-e^\frac{-1000}{1000}

P(1000<x<2000) = e^{-2}-e^{-1}

P(1000<x<2000) = 0.2325

There is a probability of 23.25% of failure in that interval.

c. Probability of failing between 0 and 1000 hours:

P(0<x<1000) = e^{\frac{-1000}{1000} }-e^\frac{-0}{1000}

P(0<x<1000) = e^{-1}-1

P(0<x<1000) = 0.6321

There is a probability of 63.21% of failing before 1000 hours.

d. P(x) = e^{\frac{-b}{1000} }-e^\frac{-a}{1000}

0.1 = 1-e^\frac{-x}{1000}

-e^{\frac{-x}{1000} }=-0.9

{\frac{-x}{1000} }=ln0.9

-x = -1000.ln(0.9)

x = 105.4

10% of the components will have failed at 105.4 hours.

5 0
3 years ago
Which expression is equivalent to (2g^3+4)^2
babunello [35]
(2g^3+4)^2= 4g^6 + 16g^3 + 16
The answer is B.
7 0
3 years ago
Read 2 more answers
Please help thank you
Allushta [10]

The average rate of change of credit card is $ 401.79 /year.

<h3>What is Average Rate?</h3>
  • A single rate that is a weighted average of the different rates that are applicable to property in various locations.
  • An average is a single number calculated as the average of a set of numbers, typically calculated as the sum of the numbers divided by the total number of numbers in the set (the arithmetic mean).

<u>Solution</u>

The difference of credit card debt between the year 2006 and 1992 = 8900 - 3275 = $5625

The difference of years between the year 2006 and 1992 = 2006 - 1992 = 14

average rate of change of credit card debt with respect to time = \frac{difference of credit card debt}{difference of years}

average rate = \frac{5625}{14} = $ 401.79 / year

know more about average numerical brainly.com/question/18296887

#SPJ4

6 0
2 years ago
Identify the figure that portrays the translation of the given preimage as indicated by the direction arrow.
ladessa [460]

The parallelogram will translate along the arrow and reach the head of the arrow.

The translation is a category of motion in which one body moves along towards a particular direction and reaches a particular point.

In translation, the rotational motion is not present. Also, the translational motion is a one-dimensional motion.

In the given figure, the parallelogram is present at the tail of the arrow.

The arrow depicts the direction of the translational motion.

So, the parallelogram will reach the end of the arrow as shown in the picture present in the attachment.

For more explanation about translation or rotation, refer to the following link:

hhttps://brainly.com/question/9032434

#SPJ10

6 0
2 years ago
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