Let A( t , f( t ) ) be the point(s) at which the graph of the function has a horizontal tangent => f ' ( t ) = 0.
But, f ' ( x ) = [ ( x^2 ) ' * ( x - 1 ) - ( x^2 ) * ( x - 1 )' ] / ( x - 1 )^2 =>
f ' ( x ) = [ 2x( x - 1 ) - ( x^2 ) * 1 ] / ( x - 1 )^2 => f ' ( x ) = ( x^2 - 2x ) / ( x - 1 )^2;
f ' ( t ) = 0 <=> t^2 - 2t = 0 <=> t * ( t - 2 ) = 0 <=> t = 0 or t = 2 => f ( 0 ) = 0; f ( 2 ) = 4 => A 1 ( 0 , 0 ) and A 2 ( 2 , 4 ).
To solve this problem we need to know the equivalence between yards and inches, that is:
1 yd = 36 inches
Therefore in 8 yd we have:
8(36) = 288
so in 8 yd we have 288 inches
So 8 yd is equal to 288 in
The best way to find your answer is to divide 193 by 400 to get .4825 and to make sure if it is the answer you take 400 and multiply .4825 and it will be 193 so .4825 = 48.25%
Answer:
See below
Step-by-step explanation:
IN a right triangle , remember S-O-H-C-A-H-T-O-A <===memorize this!
sin z = O/H = opposite side/hypotenuse = 16/20
cos z = A/H = adjacent / hy[potenuse = 12/20
tan z = O/A = 16/12
Answer:
4/5 of 3 = 12/5
2/9 of 20 = 40/9
Step-by-step explanation:
