The correct comparison for Weeks 5-8 is higher than Week 1-4, hence, the job satisfaction for Week 5-8 is 17% higher.
<u>Job Satisfaction Score</u> :
- Week 1 = 3.50
- Week 2 = 3.40
- Week 3 = 3.30
- Week 4 = 3.60
- Week 5 = 4.20
- Week 6 = 4.00
- Week 7 = 4.10
- Week 8 = 3.90
<u>Job Satisfaction for week 1 - 4</u> :
- Week 1 + Week 2 + Week 3 + Week 4
- (3.50 + 3.40 + 3.30 + 3.60) = 13.80
<u>Job Satisfaction for Week 5 - 8</u> :
- Week 5 + Week 6 + Week 7 + Week 8
- (4.20 + 4.00 + 4.10 + 3.90) = 16.20
<u>Difference</u><u> between the two categories</u> :
[(Week 5 - 8) - (Week 1-4)] / Week 1-4] × 100%
(16.20 - 13.80) / 13.80 × 100%
(2.4 / 13.80) × 100%
0.1739 × 100%
= 17.39%
Therefore, the job satisfaction for Week 5 - 8 is about 17% higher than Week 1 - 4
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Answer B
I could be wrong
Explanation
Step 1: We make the assumption that 498 is 100% since it is our output value.
Step 2: We next represent the value we seek with $x$x.
Step 3: From step 1, it follows that $100\%=498$100%=498.
Step 4: In the same vein, $x\%=4$x%=4.
Step 5: This gives us a pair of simple equations:
$100\%=498(1)$100%=498(1).
$x\%=4(2)$x%=4(2).
Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS
(left hand side) of both equations have the same unit (%); we have
$\frac{100\%}{x\%}=\frac{498}{4}$
100%
x%=
498
4
Step 7: Taking the inverse (or reciprocal) of both sides yields
$\frac{x\%}{100\%}=\frac{4}{498}$
x%
100%=
4
498
$\Rightarrow x=0.8\%$⇒x=0.8%
Therefore, $4$4 is $0.8\%$0.8% of $498$498.