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FromTheMoon [43]
4 years ago
13

The coinage metals (Group 1B) copper, silver, and gold have specific heats of 0.385, 0.233, and 0.129 J/g-K, respectively. Among

this group, the specific heat capacity and the molar heat capacity as the atomic weight increases.
(a) increases, increases.

(b) increases, decreases.

(c) decreases, increases.

(d) decreases, decreases
Chemistry
2 answers:
gladu [14]4 years ago
7 0

Answer:

D

Explanation:

The specific heat capacity is the heat required to raise the temperature of 1kg of a substance by 1oC. Molar heat capacity of a substance is the heat requiredto raise the temperature of 1mole of a substance by 1oC. Molar heat capacity and specific heat capacity both decreases with increase in atomic weight. Increase in atomic weight also means increase in density of the substance.

samsamshei3 years ago
0 0

d. since SHP = q/(mass x delta T), mass and SHP have inverse relationship

samsamshei
3 years ago
so as mass increases the SHC* decreases
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Using Equation (10), calculate [Ag+] in the cell, where it is in equilibrium with 1 M Cl- ion. (Ecell in Equation (10) is the ne
mixer [17]

Answer:

7.16x10⁻⁸M = [Ag+]

Explanation:

Using the equation:

E(Cell) =E⁰ - 0.0592/2 • log ([Cu2+]/[Ag+]²)

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<em />

Replacing:

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5 0
3 years ago
Cu + 2 AgNO3 + Cu(NO3)2 + 2Ag
Allushta [10]

Answer:

7.28 moles Ag°

Explanation:

              Cu°          +    2 AgNO₃  => Cu(NO₃)₂ + 2Ag°

Given 7.28 moles     7.28 moles

To determine limiting reactant, divide the mole values by the respective coefficient of balanced equation. The resulting smallest value is the limiting reactant. Note: this is a short cut method for determining limiting reactant only. Once the limiting reactant is determined one must use the given mole values of the limiting reactant to solve problem. That is ...

Limiting reactant determination:

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Cu: 7.28 / 1  = 7.28

AgNO₃ : 7.28 / 2 = 3.64 => Limiting Reactant is AgNO₃

Solving Problem depends on AgNO₃; Cu will be in excess.

Since coefficients of AgNO₃ & Ag° are equal, then the moles AgNO₃ used equals moles Ag° produced and is therefore 7.28 moles Ag°.

5 0
3 years ago
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