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Galina-37 [17]
3 years ago
14

If K3PO4= 0.250M, how many grams of K3PO4 are in 750.0ml of solution? Remember that M is the same as mol/L. Answer: 39.8g

Chemistry
1 answer:
sweet-ann [11.9K]3 years ago
4 0

Answer:

See below

Explanation:

Molarity = moles/Volume in Liters = (grams/formula wt)/Vol in Liters

=> Grams of solute = Molarity x Vol in Liters x formula wt

= (0.250M)(0.750L)(212.3g/mol)

= 39.8 grams

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1. A 225-L barrel of white wine has an initial free SO2 concentration of 22 ppm and a pH of 3.70. How much SO2 (in grams) should
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