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Galina-37 [17]
3 years ago
14

If K3PO4= 0.250M, how many grams of K3PO4 are in 750.0ml of solution? Remember that M is the same as mol/L. Answer: 39.8g

Chemistry
1 answer:
sweet-ann [11.9K]3 years ago
4 0

Answer:

See below

Explanation:

Molarity = moles/Volume in Liters = (grams/formula wt)/Vol in Liters

=> Grams of solute = Molarity x Vol in Liters x formula wt

= (0.250M)(0.750L)(212.3g/mol)

= 39.8 grams

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How many grams of propanol (C3H7OH, 60.10 g/mol) would be needed to make 750 mL of a solution with an osmotic pressure of 25 atm
Ierofanga [76]
Answer:

= 46.06 grams

Explanation:

P=cRT

25 = c (0.0821)(298)

concentration = c = 1.021 M

number of moles = (1.021)(0.75) = 0.7664 moles

mass = (0.7664)(60.10)=40.06 grams
3 0
3 years ago
A 10.0 g pat of butter raise the water level in a graduated cylinder by 11.6 mL. What is the density of the butter
Nina [5.8K]

- formula for density is mass divided by volume

therefore density of butter = 10.0g divided by 11.6ml = 0.8620689 g/cm³ ≈ 0.862 g/cm³ (3sf)

8 0
3 years ago
Atoms of arsenic (As) are often added to silicon (Si) in a process called doping to change the conductivity of the silicon. How
IRINA_888 [86]

Answer:

d) An atom of arsenic has one more valence electron and more electron shells than an atom of silicon, so the conductivity increases because the arsenic atom loses the electron.

Explanation:

This is an example of a n-type semiconductor. The additional electron introduced to the 'grid' of silicon atoms causes an increase in the conductivity of the silicon. This additional electron is introduced as arsenic loses its extra electron.

5 0
3 years ago
Read 2 more answers
What is the empirical formula for naphthalene
german

1.Start with the number of grams of each element, given in the problem.

2.Convert the mass of each element to moles using the molar mass from the periodic table.

3.Divide each mole value by the smallest number of moles calculated.

4.Round to the nearest whole number. This is the mole ratio of the elements and is.

5 0
3 years ago
Certain hydrocarbon is 92.3 % carbon and 7.7 % hydrogen by mass.If the molar mass of the hydrocarbon is approximately 40 g/mol,
zimovet [89]

Answer:

The hydrocarbon has a molecular formula of C3H3

Explanation:

Step 1: Data given

Suppose the mass of the compound is 100 grams

A hydrocarbon contains:

 ⇒ 92.3 % carbon = 92.3 grams

 ⇒ 7.7 % hydrogen = 7.7 grams

Molar mass of the compound is 40 g/mol

Molar mass of carbon = 12.01 g/mol

Molar mass of hydrogen = 1.01 g/mol

Step 2: Calculate moles

Moles = mass / molar mass

Moles carbon = 92.3 grams / 12.01 g/mol

Moles carbon = 7.69 moles

Moles hydrogen = 7.70 grams / 1.01 g/mol

Moles hydrogen = 7.62

Step 3: Calculate mol ratio

We divide by the smallest amount of moles

Carbon: 7.69/7.62 = 1

Hydrogen: 7.62/7.62 = 1

The empirical formula is CH

The molar mass is 13.02 g/mol

Step 4: Calculate the molecular formula

n = 40 g/mol / 13.02 g/mol

n ≈ 3

We need to multiply the empirical formula by 3 to get the molecular formula

Molecular formula = 3*(CH) = C3H3

The hydrocarbon is C3H3

5 0
3 years ago
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