Answer:
i dont get your question Man
Answer:
work done = force multiplied by distance covered,which is 500n multiplied by 20 m= 10000nm
power= work done/time
p= 10000/10
p=1000
Answer:
I think you use sig figs in percent error.
The wick and the wax
Sorry if that was useless, I'm not sure how generalized you were being
Answer:
The appropriate answer is "9.225 g".
Explanation:
Given:
Required level,
= 63 ppm
Initial concentration,
= 22 ppm
Now,
The amount of free SO₂ will be:
= 
= 
= 
The amount of free SO₂ to be added will be:
= 
= 
∵ 1000 mg = 1 g
So,
= 
= 
Thus,
"9.225 g" should be added.