Given:
ft and
ft.

To find:
The value of P.
Solution:
We have,

Substituting
and
, we get




Taking LCM, we get




Therefore, the value of P is
ft.
Answer:
#7: MK, LS and PR
#8: PN and PQ
#9: no
#10: no
Step-by-step explanation:
#7: lines MK, LS and PR are not intersecting each other, so these lines are parallel each other
#8: between lines PN and PQ is an right angle, so the lines PN and PQ are perpendicular
#9: lines PN and KM have an intesecting point, so they're not parallel
#10: there is no right angle between lines PR and NP
Answer:
The potential energy of the ball having 2kg mass would be
J
Step-by-step explanation:
I am assuming the ball has a mass of 2 kg, as you have not mentioned the mass of a ball.
Considering the formula for calculating the gravitational potential energy

As
kg
Acceleration of gravity = g = 9.8 
As the ball is on the height = h = 20 meters
So,

J
Therefore, the potential energy of the ball =
J
Keywords: potential energy, Gravitation potential energy
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I think we’re talking about the 15, the smallest number for 15 would be 3. Because 3 x 5 = 15
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