The test score for a class are shown. What is the average test score? 79,80,92,92,81,100,88,98,71,100,91,90
Oksanka [162]
Answer:
The average score is equal to 88.5
Step-by-step explanation:
we know that
An average test score is the sum of all the scores on an assessment divided by the number of test-takers.
so
The sum is equal to
![Sum=[79+80+92+92+81+100+88+98+71+100+91+90]=1,062](https://tex.z-dn.net/?f=Sum%3D%5B79%2B80%2B92%2B92%2B81%2B100%2B88%2B98%2B71%2B100%2B91%2B90%5D%3D1%2C062)
The number of test-takers is n=12
The average score is equal to
substitute
Answer:
The answer is 18
Step-by-step explanation:
Answer:
56
Step-by-step explanation:
I assume each person in the group must have 1 pencil AND 1 eraser each.
Since you have more pencils than erasers, then the limiting factor is the number of erasers. So a group of 56 people will have 1 pencil And 1 eraser and Clare will have 24 pencils left over (assuming Clare has her own pencil and eraser - if not then the group size is 55 assuming Clare is not in the group)
sorry if it's too confusing
The center of a circle whose equation is x^2 +y^2 – 12x – 2y +12 = 0 is (6,1)
<h3>Equation of a circle</h3>
The standard equation of a circle is expressed as:
x^2 + y^2 + 2gx + 2fy + c = 0
where:
(-g, -f) is the centre of the circle
Given the equations
x^2 +y^2 – 12x – 2y +12 = 0
Compare
2gx = -12x
g = -6
Simiarly
-2y = 2fy
f = -1
Centre = (6, 1)
Hence the center of a circle whose equation is x^2 +y^2 – 12x – 2y +12 = 0 is (6,1)
Learn more on equation of a circle here: brainly.com/question/1506955
Step-by-step explanation:
good morning
but its 16.53 here
