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Kruka [31]
3 years ago
7

Simplify the expression 200y+30+110-75y×2+y

Mathematics
1 answer:
vichka [17]3 years ago
4 0
The answer would be 51y+140
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A number increased by 24 is 112. what is the number
dexar [7]
I believe the correct number is 88.
8 0
2 years ago
Let f(x)=1/x and g(x)=x^2-2. What is (fog)(-3)?
Elenna [48]

Answer:

Its value is 1/7.

I hope this will help you.

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20-%200.4%20%2B%201.5%283.1%29" id="TexFormula1" title=" - 0.4 + 1.5(3.1)" alt=" - 0.4 + 1.5(
ANTONII [103]
Hi,

- 0.4  + 1.5(3.1) \\  - 0.4 + 1.5 \times 3.1 \\  - 0.4 + 4.65  = 4.25


Hope this helps.
r3t40
8 0
3 years ago
How many different combinations are possible if each lock contains the numbers 0 to 39, and each combination contains three dist
Georgia [21]
(e) Each license has the formABcxyz;whereC6=A; Bandx; y; zare pair-wise distinct. There are 26-2=24 possibilities forcand 10;9 and 8 possibilitiesfor each digitx; yandz;respectively, so that there are 241098 dierentlicense plates satisfying the condition of the question.3:A combination lock requires three selections of numbers, each from 1 through39:Suppose that lock is constructed in such a way that no number can be usedtwice in a row, but the same number may occur both rst and third. How manydierent combinations are possible?Solution.We can choose a combination of the formabcwherea; b; carepair-wise distinct and we get 393837 = 54834 combinations or we can choosea combination of typeabawherea6=b:There are 3938 = 1482 combinations.As two types give two disjoint sets of combinations, by addition principle, thenumber of combinations is 54834 + 1482 = 56316:4:(a) How many integers from 1 to 100;000 contain the digit 6 exactly once?(b) How many integers from 1 to 100;000 contain the digit 6 at least once?(a) How many integers from 1 to 100;000 contain two or more occurrencesof the digit 6?Solutions.(a) We identify the integers from 1 through to 100;000 by astring of length 5:(100,000 is the only string of length 6 but it does not contain6:) Also not that the rst digit could be zero but all of the digit cannot be zeroat the same time. As 6 appear exactly once, one of the following cases hold:a= 6 andb; c; d; e6= 6 and so there are 194possibilities.b= 6 anda; c; d; e6= 6;there are 194possibilities. And so on.There are 5 such possibilities and hence there are 594= 32805 such integers.(b) LetU=f1;2;;100;000g:LetAUbe the integers that DO NOTcontain 6:Every number inShas the formabcdeor 100000;where each digitcan take any value in the setf0;1;2;3;4;5;7;8;9gbut all of the digits cannot bezero since 00000 is not allowed. SojAj= 9<span>5</span>
8 0
3 years ago
What is the length of ? Round to the nearest tenth. hurry please
professor190 [17]
Well from positive y axis Q is situated at 6 units while P is situated at 3 units.

So length of PQ - 6+3 = 9 units.
Rounding up your answer is 10 units

5 0
3 years ago
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