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Ann [662]
3 years ago
15

A school district is formed by a triangle web side measures 48 km 55 km and 80 km classify the triangle

Mathematics
1 answer:
user100 [1]3 years ago
8 0
Classify the triangle?  In other words, state the type of triangle we have here:  right, acute or obtuse.

If the triangle is a right triangle, then 48^2+55^2=80^2 by the Pythagorean Theorem.  Let's check that out:  We get 5329 = 6400, which is false.  So this triangle is not a right triangle.  

For this to be an obtuse triangle, 48+55 would have to be greater than 80.  That's not the case here.  Thus, the triangle is ACUTE.


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Consider the equation 3a+0.1n=123. If we solve this equation for n, which equation would result? A. 0.1n=123-3a B. N=123-3a-0.1
neonofarm [45]

Answer:

n = (123 - 3a) / 0.1

Step-by-step explanation:

Given:

3a + 0.1n = 123

Solve for n

3a + 0.1n = 123

Subtract 3a from both sides

3a + 0.1n - 3a = 123 - 3a

0.1n = 123 - 3a

Divide both sides by 0.1

n = (123 - 3a) / 0.1

The resulting equation if 3a + 0.1n = 123 is solved for n is n = (123 - 3a) / 0.1

4 0
3 years ago
Trina and her mom are planting 45 plants in their garden.if their garden is 9 square feet how many plants can they put in each s
timurjin [86]
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7 0
3 years ago
The temperature at 6:00 a.m. was -6°F. By 12 noon, the temperature had increased by 15°F. What was the temperature at
NeTakaya

Answer:

9°

Step-by-step explanation:

-6 + 15 = 9

7 0
3 years ago
The square below has an area of 22 - 10.2 + 25 square meters.
ZanzabumX [31]

Answer:

x = 1.89

Step-by-step explanation:

Solve 22 - 10.2 + 25 to get 36.8 as the square's area.

Set up the equation 36.8 = (-10x + 25)^2 to represent the relationship between one side length and the area.

Reverse the equation to solve for x! Find the square root of both sides to cancel out the exponent. This gets you: 6.07 = -10x + 25.

Subtract 25 from both sides, then divide by -10 to get x by itself.

x = 1.89

6 0
3 years ago
Plz help and thanks so much for it
kirza4 [7]
B+c+(c-b)+(b-c). That is your expression.  b 11 c 16
       
          First, let's convert the variables to real numbers:   11+16+(16-11)+(11-16)
             Now, let's solve that equation.                                    11+16+5+(-5)
                      5+(-5) cancels out, so all we have left is:                   27
                That is your perimeter.
    
7 0
3 years ago
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