Solve this system of linear equations. Separate

Mathematics

1 answer:

Sladkaya [172]3 years ago

8 0

Step-by-step explanation:

making x subject in eq 1

x= (-1-9y)/-14

substituting the value of x in eq 2

17(-1-9y/-14)=7+9y

(-17-153y)/-14=7+9y

-17-153y=-98-126y

-17+98=153y-126y

81=27y

y=3

substituting this value of y in eq 1

-14x=-1-9(3)

-14x=-28

x=2

(x,y) = (2,3)

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Solve the equation

UNO [17]

Answer:

x = 10

Step-by-step explanation:

2x/3 + 1 = 7x/15 + 3

(times everything in the equation by 3 to get rid of the first fraction)

2x + 3 = 21x/15 + 9

(times everything in the equation by 15 to get rid of the second fraction)

30x+ 45 = 21x + 135

(subtract 21x from 30x; subtract 45 from 135)

9x = 90

(divide 90 by 9)

x = 10

<h2>Another solution:</h2>

2x/3 + 1 = 7x/15 + 3

(find the LCM of 3 and 15 = 15)

(multiply everything in the equation by 15, then simplify)

10x + 15 = 7x + 45

(subtract 7x from 10x; subtract 15 from 45)

3x = 30

(divide 30 by 3)

x = 10

4 0

2 years ago

Triangle OBC is a right triangle drawn on a coordinate plane. Side OC lies on the x-axis, the coordinates of point O are (0, 0),

Rudik [331]

Long leg = 8 → opposite
short leg = 6 → adjacent
hypotenuse = ?

8² + 6² = c²
64 + 36 = c²
100 = c²
√100 = √c²
10 = c

sin ∠BOC = opposite / hypotenuse
sin ∠BOC = 8 / 10
sin ∠BOC = 0.80

tan ∠BOC = opposite / adjacent
tan ∠BOC = 8 / 6
tan ∠BOC = 1.33