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Viefleur [7K]
3 years ago
15

Let h(x) = 3x – 7. If h(x) = 0, find x.

Mathematics
2 answers:
vekshin13 years ago
4 0

\text{Plug in 0 to h(x) and solve:}\\\\0=3x-7\\\\\text{Add 7 to both sides}\\\\7=3x\\\\\text{Divide both sides by 3}\\\\\frac{7}{3}=x\\\\\boxed{\frac{7}{3}=x}

Genrish500 [490]3 years ago
3 0

h(x)=3x-7

And we are given that h(x)=0 and want to find the value of x. Set h(x) to 0 and we get the equation:

3x-7=0

Add both sides by 7

3x=7

Divide both sides by 3

x=\dfrac{7}{3}

This is the answer (as an improper fraction). Let me know if you need any clarifications, thanks!

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Hannah says that 2.11 is a rational number. Gus says that 2.11 is a repeating decimal. Who is correct and why?
shusha [124]

Answer

  • 2.11 is rational number Hannah is correct because it doesn't have 3 dots in the end if it is repeating decimal it will be (2.11.......
7 0
3 years ago
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How does adding the log together automatically mean that it is a factorial?
andreyandreev [35.5K]

Answer: The answer is given below.

Step-by-step explanation:  We are given an equality involving logarithm and we are to show the implication of L.H.S. to R.H.S.

We will be using the following two properties of logarithm:

(i)~\log_ba=\dfrac{1}{\log_ab},\\\\\\(ii)~log_ab+\log_ac=\log_a(bc).

The proof is as follows:

L.H.S.\\\\\\=\dfrac{1}{\log_2N}+\dfrac{1}{\log_3N}+\dfrac{1}{\log_4N}+\cdots+\dfrac{1}{\log_{100}N}\\\\\\=\log_N2+\logN3+\log_N4+\cdots+\log_N100\\\\=\log_N\{2.3.4...100\}\\\\=\log_N\{1.2.3.4...100\}\\\\=\log_N{100!}\\\\=\dfrac{1}{\log_{100!}N}\\\\=R.H.S.

Hence proved.

6 0
3 years ago
0.07 as a mixed number
8_murik_8 [283]
It cant be converted into a mixed number because it has no whole.
5 0
4 years ago
Helpppppppp plsssss !!
lora16 [44]

Answer:

False, A equation DOES have to have a equal sign.

Step-by-step explanation:

8 0
3 years ago
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A bag contains 2 white marbles and 7 purple marbles. Two marbles are drawn at random. One marble is drawn and not replaced. Then
Masja [62]
A.
\frac{7purple}{9total} *  \frac{2white}{8total}  \\  \frac{14}{72}  \\ =0.194
The denominator of the second number goes down one because you aren't replacing the initial marble pulled, making the amount of marbles in the bag go down, but not affecting the white count because you pulled a purple marble.
b.
\frac{2white}{9total} *  \frac{1white}{8total}  \\  \frac{2}{72}  \\ =0.278
The same can be said about the denominator for this problem, but not the numerator. The numerator must go down one number as well, because you already chose one white marble, taking one of the white marbles out of the bag, leaving you with one solitary, white marble.
c.
Chance of selecting two purple marbles:
<u />\frac{7purple}{9total} *  \frac{6purple}{8total}  \\  \frac{42}{72}  \\ =0.583
Chance of selecting two white marbles:
\frac{2white}{9total} * \frac{1white}{8total} \\ \frac{2}{72} \\ =0.278
<u>Chance of selecting two purple</u> vs. <em>Chance of Selecting 2 white:</em>
<u>0.583</u>><em>0.278</em>.
It is more likely to select 2 purple marbles.

Hope this helps!
6 0
3 years ago
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