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3 years ago

Which is a characteristic of an Atoms

Chemistry

1 answer:

Rama09 [41]3 years ago

6 0

Answer:

2. they are the smallest unit of matter

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If an ideal gas at a constant temperature is initially at a pressure of 3.8 atm and is then allowed to expand to a volume of 5.6

BabaBlast [244]

Answer:

The most common example is the molar volume of a gas at STP (Standard Temperature and Pressure), which is equal to 22.4 L for 1 mole of any ideal gas at a temperature equal to 273.15 K and a pressure equal to 1.00 atm.If an ideal gas at a constant temperature is initially at a pressure of 3.8 atm and is then allowed to expand to a volume of 5.6 L and a pressure of 2.1 - 18914… ... of 5.6 L and a pressure of 2.1 atm, what is the initial volume of the gas? ... An ideal gas is at a pressure of 1.4 atm and has a volume of 3 L.

Explanation:

I hope I help :)

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3 years ago

Advantage of modern perodic law

mario62 [17]

Answer:

it has made the study of chemistry systematic and easy. it acts as an aid to memory

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2 years ago

Express 7.25 in scientific notation

sergeinik [125]

Considering that scientific notation has to move the decimal over so there is only one digit in the Tens place, that is the scientific notation.

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3 years ago

Read 2 more answers

Show your work with good use of units, rounding, and significant figures. [Hint: it is good practice to show the value of your a

mel-nik [20]

Heat required : 4.8 kJ

<h3>Further explanation </h3>

The heat to change the phase can be formulated :

Q = mLf (melting/freezing)

Q = mLv (vaporization/condensation)

Lf=latent heat of fusion

Lv=latent heat of vaporization

The heat needed to raise the temperature

Q = m . c . Δt

1. heat to raise temperature from -20 °C to 0 °C

$\tt Q=10\times 2.09\times (0-(-20)=418~J$

2. phase change(ice to water)

$\tt Q=10\times 333=3330~J$

3. heat to raise temperature from 0 °C to 25 °C

$\tt Q=10\times 4.18\times (25-0)=1045~J$

$\tt Q~tot=418+3330+1045=4793~J\rightarrow rounding~and~2~sig~figs=4.8~kJ$

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2 years ago

The melting point of the metal potassium is 63.5c, while that of titanium is 1660c. what explanation can be given for this great

kiruha [24]

The melting point of potassium = $63.5^{0}C$

Melting point of titanium = $1660^{0}C$

Titanium has a stronger metallic bonding compared to potassium. Titanium being a transition metal has greater number of valence electrons (4 valence electrons) contributing to the valence electron sea compared to potassium which has only one valence electron. The atomic size of Titanium much lower than that of potassium, so the bonding between Titanium atoms is stronger than that of potassium. Hence, the melting point of Titanium is much higher than that of potassium.

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3 years ago