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daser333 [38]
3 years ago
7

Molarity is not fun... Help please!

Chemistry
1 answer:
Ainat [17]3 years ago
3 0
I believe the first one, forgive me if I’m wrong, I’m not completely sure
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Electromagnetic energy that travels in transverse waves which produces visible light is
Lubov Fominskaja [6]
Nuclear is the answer
8 0
3 years ago
Gold forms face-centered cubic crystals. The atomic radius of a gold atom is 144 pm. Consider the face of a unit cell with the n
kipiarov [429]

Answer:

The length of an edge of this unit cell is 407.294 pm

Explanation:

Face centered cubic structure contains 4 atoms in each unit cell and 12 coordination number, occupying about 74% volume of the total cell. Face centered cubic structure is known for efficient use of space for atom packing.

To determine the edge length, a relationship between the radius of the atom and edge length is used.

X = R√8

Where;

X is the length of an edge of this unit cell

R is the radius of the gold atom = 144 pm = 144 X 10⁻¹² m

X = 144 X 10⁻¹²√8

X = 407.294 X 10⁻¹² m

X = 407.294 pm

Therefore, the length of an edge of this unit cell is 407.294 pm

8 0
3 years ago
Josh is washing glasses with soap and water. He is afraid to
Maru [420]
He could dry them with a towel.
4 0
3 years ago
Read 2 more answers
Atomic orbitals developed using quantum mechanics describe regions of space in which one is most likely to find an electron. giv
valina [46]

Answer:

Option A is correct.

Atomic orbitals developed using quantum mechanics describe regions of space in which one is most likely to find an electron

Explanation:

Atomic orbitals developed using quantum mechanics make use of quantum numbers.

There are four different quantum numbers that all work to give the region of space where a particular electron has the highest probability of being located.

The four quantum numbers that describes an electron's most likely location in an atom include

1) Principal quantum number, denoted by letter n. This quantum number gives the shell that an electron in an atom belongs to. It can take on natural number values from 1 (for the shell closest to the nucleus) through 2, 3, 4.... till rhe outermost shell.

2) Azimuthal/Angular Momentum quantum number, denoted by l. This quantum number describes the subshell or orbital within a shell that the electron belongs to in an atom.

It can take on values that can range from 0 to (n-1). These are the spdf orbitals with s-orbital having l-quantum number of 0, p-orbital with l-quantum number of 1 etc.

3) Magnetic quantum number, denoted by letter m. This describes the sub-orbital that the electron belongs to. It's values for electrons in a particular orbital vary from -l through 0 to +l.

E.g. orbital with l = 1 has electrons whose magnetic quantum number vary from -1, 0, +1.

orbital with l = 2 has electrons whose magnetic quantum number vary from -2, -1, 0, +1, +2.

4) Spin quantum number, denoted by letter s.

This describes the orientation of the electron's spin. Whether clockwise or anti-clockwise in it's sub-orbital. It can take on only values of (+1/2) or (-1/2).

So, these four quantum numbers, numbers that were made known because of quantum mechanics, show that atomic orbitals developed using quantum mechanics describe regions of space in which one is most likely to find an electron in an atom.

Hope this Helps!!!

5 0
3 years ago
If you have 16 g of manganese (II) nitrate tetrahydrate, how much water is required to prepare 0.16 M solution from this amount
nirvana33 [79]

<u>Answer:</u> The volume of water required is 398 mL

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Mass of solute (manganese (II) nitrate tetrahydrate) = 16 g

Molar mass of manganese (II) nitrate tetrahydrate = 251 g/mol

Molarity of solution = 0.16 M

Putting values in above equation, we get:

0.16M=\frac{16g\times 1000}{251g/mol\times \text{Volume of solution}}\\\\\text{Volume of solution}=398mL

Hence, the volume of water required is 398 mL

7 0
3 years ago
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