Moles of solute does not change.
mass of carbonic acid = 300g
molar mass of H2CO3 = 2H + C + 3 O
= 2 x 1.008+ 12.01 + 3 x 16
= 62.03g/mol
moles of H2CO3 = mass/Molar mass
= 300/62.03
= 4.8364 moles
1 mole H2CO3 has 3 moles Oxygen
4.8364 moles H2CO3 contains
= 3 x 4.8364 moles Oxygen = 14.509 moles Oxygen
moles = mass/Molar mass
mass of oxygen = moles x Molar mass of Oxygen
= 14.509 x 16
= 232.15g Oxygen
mass of oxygen in 300g of carbonic acid(H2CO3) = 232.15g
Answer:
the number of possible configurations of the locations and energies of the atoms or molecules that comprise a system
Explanation:
Ludwig Boltzmann was the first to suggest that the concept of entropy could be calculated by examining the positions and energies of molecules. This was developed into an equation, known as the Boltzmann equation, which relates entropy to the number of microstates (W):
S = k ln W
where k is the Boltzmann constant (1.38 x 10-23 J/K), and W is the number of microstates.
Microstates was used to imply the number of different possible arrangements of molecular position and kinetic energy at a particular thermodynamic state. Therefore any process that gives an increase in the number of microstates therefore increases the entropy. Hence the answer.
Answer:
3.50*10^-11 mol3 dm-9
Explanation:
A silver rod and a SHE are dipped into a saturated aqueous solution of silver oxalate, Ag2C2O4, at 25°C. The measured potential difference between the rod and the SHE is 0.5812 V, the rod being positive. Calculate the solubility product constant for silver oxalate.
Ag2C2O4 --> 2Ag+ + C2O4 2-
So Ksp = [Ag+]^2 * [C2O42-]
In 1 L, 2.06*10^-4 mol of silver oxalate dissolve, giving, the same number of mol of oxalate ions, and twice the number of mol (4.12*10^-4) of silver ions.
So Ksp = (4.12*10^-4)^2 * (2.06*10^-4)
= 3.50*10^-11 mol3 dm-9
He atom<span> consists of a tiny </span>nucleus<span> surrounded by moving electrons. </span>
