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torisob [31]
3 years ago
8

Higher organisms use nitrogen to make their______________ will mark brainliest

Chemistry
1 answer:
olganol [36]3 years ago
5 0

Answer:

rogen is a crucially important component for all life. It is an important part of many cells and processes such as amino acids, proteins and even our DNA. It is also needed to make chlorophyll in plants, which is used in photosynthesis to make their food.

Explanation:

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What does Br2 stand for
LuckyWell [14K]
The element Bromine is known as the chemical symbol Br2
8 0
3 years ago
A compound that present in many foods has the formula c44h86o8np. to which class of molecules does this compound belong? explain
Semmy [17]

Answer : Lipids.

Explanation : The compound molecule of C_{44}H_{86}O_{8}NP is a compound called as MMPE. MMPE stands for monomethylphosphatidylethanolamine. It belongs to the class of lipids and is widely present in many food.

3 0
4 years ago
Read 2 more answers
A liquid used to dissolve a solid is referred to as:
ale4655 [162]
A solvent and an example would be water because it is polar and has the ability to dissolve many solutes, hence it is referred to as the universal solvent.
4 0
3 years ago
A 5-kg quantity of radioactive isotope decays to 2 kg after 10 years. Find the decay constant of the isotope.k = _____
Dvinal [7]

Answer:

k = -0.09165 years^(-1)

Explanation:

The exponential decay model of a radioactive isotope is generally given as;

A(t) = A_o(e^(kt))

Where;

A_o is quantity of isotope before decay, k is decay constant and A(t) is quantity after t years

We are given;

A_o = 5 kg

A(10) = 2kg

t = 10 years

Thus;

A(10) = 2 = 5(e^(10k))

Thus;

2 = 5(e^(10k))

2/5 = (e^(10k))

0.4 = (e^(10k))

In 0.4 = 10k

-0.9164 = 10k

k = -0.9164/10

k = -0.09165 years^(-1)

7 0
3 years ago
For the following reaction, 3.70 grams of oxygen gas are mixed with excess carbon monoxide . The reaction yields 8.25 grams of c
Elden [556K]

Answer:

81% Yield

Explanation:

2CO        +               O₂                                =>     2CO₂

Excess                3.70g O₂                          =>     8.25g CO₂ (actural yield)

               (3.70g O₂)/(32g O₂/mol O₂)

                   = 0.1156 mol O₂                       =>  2(0.1156) mol CO₂

                                                                          = 10.175g (Theoretical Yield)

%Yield = (Actual Yield / Theoretical Yield)100%  

= (8.25g/10.175g)100% = 81% Yield

4 0
3 years ago
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