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son4ous [18]
3 years ago
15

Convert 61 μg of aluminum phosphate to grams. (Hint: 1 μg = 1 x 10-6 g, so multiply 61 by 1 x 10-6)

Chemistry
1 answer:
diamong [38]3 years ago
7 0

Answer: 61 μg of aluminum phosphate in grams is equal to 61 \times 10^{-6} g.

Explanation:

According to standard conversion of units, 1 microgram (\mu g) is equal to 1 \times 10^{-6} g.

Therefore, 61 \mu g is converted into grams as follows.

1 \mu g = 10^{-6} g\\61 \mu g = 61 \mu g \times \frac{10^{-6}}{1 g}\\= 61 \times 10^{-6} g

Thus, we can conclude that 61 μg of aluminum phosphate in grams is equal to 61 \times 10^{-6} g.

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Answer:

The empirical formula is Li2CO3

Explanation:

Step 1: Data given

Suppose the mass of the compound = 100 grams

The compound contains :

18.7% Li = 18.7 grams of Li

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Molar mass of Li = 6.94 g/mol

Molar mass of C = 12.01 g/mol

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Step 2: Calculate moles

Moles = Mass / molar mass

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Step 3: Calculate the mol ratio

We divide by the smallest number of moles

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C: 1.36/1.36 = 1

O: 4.06/1.36 ≈ 3

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