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son4ous [18]
3 years ago
15

Convert 61 μg of aluminum phosphate to grams. (Hint: 1 μg = 1 x 10-6 g, so multiply 61 by 1 x 10-6)

Chemistry
1 answer:
diamong [38]3 years ago
7 0

Answer: 61 μg of aluminum phosphate in grams is equal to 61 \times 10^{-6} g.

Explanation:

According to standard conversion of units, 1 microgram (\mu g) is equal to 1 \times 10^{-6} g.

Therefore, 61 \mu g is converted into grams as follows.

1 \mu g = 10^{-6} g\\61 \mu g = 61 \mu g \times \frac{10^{-6}}{1 g}\\= 61 \times 10^{-6} g

Thus, we can conclude that 61 μg of aluminum phosphate in grams is equal to 61 \times 10^{-6} g.

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A chain volcano would be my answer
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. The electron affinity for an oxygen atom is negative. What statement is probably true regarding
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The best and most correct answer among the choices provided by your question is the second choice or letter B.

<span>Regarding the second electron affinity for an oxygen, i. e., the electron affinity for O-, it is much larger and negative.</span>

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Cite two important quantum-mechanical concepts associated with the Bohr model of the atom.(b) Cite two important additional refi
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Explanation:

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3 years ago
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0.023 M solution of perchloric acid
kogti [31]
The original question is to find the pH and the pOH of 0.023 M of perchloric acid.

Answer:
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pOH = 12.362

Explanation:
1- getting the pH:
pH can be calculated using the following rule:
pH = -log[H+]
Since the given solution is an acid, this means that [H+] is the same as the concentration of the solution.
This means that:
[H+] = 0.023
Substitute in the above equation to get the pH as follows:
pH = -log[0.023]
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2- getting the pOH:
We know that:
pH + pOH = 14
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Substitute in the above equation to get the pOH as follows:
pOH + 1.638 = 14
pOH = 14 - 1.638
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Hope this helps :)
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3 years ago
Why does perchloric acid cause macromolecules to precipitate?
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