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4 years ago

Find all numbers whose absolute value is 6

Mathematics

1 answer:

natulia [17]4 years ago

8 0

♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫

➷The answer is 6 and -6.

Since absolute value is to figure the distance from 0, it is regardless of positive or negative.

6, -6 are the only numbers.

✽

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

DOGE

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The first two classes of a frequency distribution are 0-9 and 10-19. What is the class width?

likoan [24]

Answer: (a) 9

Step-by-step explanation:

We are given that ,

The first two classes of a frequency distribution are 0-9 and 10-19.

We know that the class width of an class interval is basically the difference between the upper limit and the lower limit of the interval.

For example the class interval for interval 40 - 45 is 5 because 45-40=5.

For the given class interval 0-9 , upper limit= 9

Lower limit =0

⇒ Class width = 9-0= 9

Similarly , for 10-19 , the class width = 19-10=9

Therefore , the class width is 9 .

Hence, the correct answer is (a) 9.

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I need help ASAP <br><br> I also need to do work on it for homework

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Answer:

120 in

Step-by-step explanation:

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$A = b * h$

For this problem, the base is 15 in while the height is 8 in. Plug in the numbers into the equation and solve.

$A = b * h$

$A = 15 * 8$

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URGENT!!!!

babunello [35]

The equation of the hyperbola in standard form is $\frac{(y-4)^{2}}{100}-\frac{(x-1)^{2}}{64}=1$

Step-by-step explanation:

Let us revise the equation of the hyperbola

The standard form of the equation of a hyperbola with center (h , k) and transverse axis parallel to the y-axis is $\frac{(y-k)^{2}}{a^{2}}-\frac{(x-h)^{2}}{b^{2}}=1$

The length of the transverse axis is 2a
The length of the conjugate axis is 2b

∵ The center of the hyperbola is (1 , 4)

∴ h = 1 and k = 4

∵ The transverse axis is parallel to the y-axis

∴ The form of the equation is $\frac{(y-k)^{2}}{a^{2}}-\frac{(x-h)^{2}}{b^{2}}=1$

∴ The length of the transverse axis is 2a

∵ The length of the transverse axis is 20 units

- Equate 2a by 20 to find a

∴ 2a = 20

- Divide both sides by 2

∴ a = 10

∵ The length of the conjugate axis is 2b

∵ The length of the conjugate axis is 16

- Equate 2b by 16 to find b

∴ 2b = 16

- Divide both sides by 2

∴ b = 8

- Substitute the values of h, k, a, and b in the form of the equation

∴ $\frac{(y-4)^{2}}{(10)^{2}}-\frac{(x-1)^{2}}{(8)^{2}}=1$

∴ $\frac{(y-4)^{2}}{100}-\frac{(x-1)^{2}}{64}=1$

The equation of the hyperbola in standard form is $\frac{(y-4)^{2}}{100}-\frac{(x-1)^{2}}{64}=1$

Learn more:

You can learn more about the hyperbola in brainly.com/question/4054269

#LearnwithBrainly

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Find all numbers whose absolute value is 6​

Find all numbers whose absolute value is 6