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3 years ago

Neon's outer energy level contains ______________ electrons. A) 2 B) 8 C) 10 D) 20

Chemistry

2 answers:

weeeeeb [17]3 years ago

8 0

Its 8 which is b good luck (:

yuradex [85]3 years ago

7 0

B) 8

Neon is a noble gas which means it is in the 18th group which has 8 valence electrons. Thus Neon has 8 valence electrons.

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Why k has more shielding effect than Na?

lara [203]

Explanation:

As the charge of all electrons are equal, the repulsive force exerted by each of them is also going to be equal. So, as K has more electrons repulsing its valence electron than Na, it has greater electron shielding.

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3 years ago

What are some real world applications in which ph is an important factor?

Blababa [14]

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3 years ago

True or false

Kaylis [27]

Answer:

True

Explanation:

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Example :

Blasting a balloon by compressing it tightly with both hands, roughly with an equal force, is a practical example of Balanced Forces. In this case, the balloon before the burst stays at a state of rest and same after the burst. But the burst or the compression, causes a change in the shape of the balloon.

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3 years ago

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iren [92.7K]

Answer:

the net force us 0.............

Explanation:

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3 years ago

The normal freezing point of water is 0.00 ⁰C. What is the freezing point of a solution containing450.0 mg of ethylene glycol (M

anyanavicka [17]

Answer:

Freezing T° of solution = - 8.98°C

Explanation:

We apply Freezing point depression to solve this problem, the colligative property that has this formula:

Freezing T° of pure solvent - Freezing T° of solution = Kf . m

Kf = 1.86°C/m, this is a constant which is unique for each solvent. In this case, we are using water

m = molality (moles of solute / 1kg of solvent)

We convert the mass of solvent from g to kg

1.5 g . 1kg/1000g = 0.0015 kg

We convert the mass of solute, to moles. Firstly we make this conversion, from mg to g → 450mg . 1g/1000mg = 0.450 g

0.450 g. 1mol / 62.07g = 7.25×10⁻³ moles

Molality → 7.25×10⁻³ mol / 0.0015 kg = 4.83 m

- Freezing T° of solution = 1.86°C /m . 4.83 m - Freezing T° of pure solvent

-Freezing T° of solution = 1.86°C /m . 4.83 m - 0°C

Freezing T° of solution = - 8.98°C

8 0

3 years ago

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