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Vikentia [17]
3 years ago
9

What is the density (g/mL) of an object that has a mass of 0.03 kg and occupies a volume of 25 mL?

Chemistry
2 answers:
tatyana61 [14]3 years ago
5 0
First convert the kg to g ----- 0.03kg = 30g
Then divide the mass by the volume ----- 30g ÷ 25mL = 1.2
The density is 1.2g/mL<span />
zavuch27 [327]3 years ago
3 0

Answer : The density of an object is 1.2 g/mL

Explanation :

Density : It is defined as the mass contained per unit volume.

Formula used :

Density=\frac{Mass}{Volume}

Given :

Mass of object = 0.03 kg = 30 g

conversion used : (1 kg = 1000 g)

Volume occupied by object = 25 mL

Now put all the given values in the above formula, we get :

Density=\frac{30g}{25mL}=1.2g/mL

Therefore, the density of an object is 1.2 g/mL

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Electron affinity is the measure of the attraction of an electron toward an isolated gaseous atom. When an electron is added to
zhuklara [117]

False

Explanation:

Electron affinity is negative when energy is absorbed and it is positive when energy is released.

Electron affinity is defined as the energy released in adding an electron to a neutral atom in the gas phase.

It is a measure of the readiness of an atom to gain an electron.

In a reaction where energy is released, electron affinity is usually positive. These reactions are called exothermic reactions.

Endothermic reactions in which energy is absorbed have negative electron affinity values.

Learn more:

Endothermic reactions brainly.com/question/12964401

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3 years ago
How many total electrons can the p orbitals hold?<br> A. 6<br> B. 2<br> C. 10<br> D. 3
mars1129 [50]

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A. 6

Explanation:

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As the speed of a particle increases, does its associated wavelenght increase or decrease
Zina [86]

The de Broglie hypothesis proposed that all particles have wave-like properties, with the wavelength being inversely proportional to the velocity of the particle.


Therefore as the velocity (speed in this question) increases, the wavelength *decreases*.

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Which of the following statements is true about the nucleus?
vlabodo [156]

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Determine the molar mass of CuSO4 (the solute) in a 1.0M aqueous solution of CuSO4
inna [77]

Answer:

See explanation.

Explanation:

Hello,

In this case, we could have two possible solutions:

A) If you are asking for the molar mass, you should use the atomic mass of each element forming the compound, that is copper, sulfur and four times oxygen, so you can compute it as shown below:

M_{CuSO_4}=m_{Cu}+m_{S}+4*m_{O}=63.546 g/mol+32.00g/mol+4*16.00g/mol\\\\M_{CuSO_4}=159.546g/mol

That is the mass of copper (II) sulfate contained in 1 mol of substance.

B) On the other hand, if you need to compute the moles, forming a 1.0-M solution of copper (II) sulfate, you need the volume of the solution in litres as an additional data considering the formula of molarity:

M=\frac{n_{solute}}{V_{solution}}

So you can solve for the moles of the solute:

n_{solute}=M*V_{solution}

Nonetheless, we do not know the volume of the solution, so the moles of copper (II) sulfate could not be determined. Anyway, for an assumed volume of 1.5 L of solution, we could obtain:

n_{solute}=1mol/L*1.5L=1.5mol

But this is just a supposition.

Regards.

4 0
3 years ago
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