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Pani-rosa [81]
4 years ago
9

4.77 l and a mass of 12.88 kg what is the density of the aluminum in grams per cubic centimeter

Chemistry
1 answer:
ra1l [238]4 years ago
6 0
V=4,77L=4770mL\\
m=12,88kg=12880g\\\\
d=\frac{m}{V}=\frac{12880g}{4770cm^{3}}\approx2,7\frac{g}{cm^{3}}
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A sample of helium gas initially at 37.0°C, 785 torr and 2.00 L was heated to 58.0°C while the volume expanded to 3.24 L. What i
spayn [35]

Answer:

0.681 atm

Explanation:

To solve this problem, we make use of the General gas equation.

Given:

P1 = 785 torr

V1 = 2L

T1 = 37= 37 + 273.15 = 310.15K

P2 = ?

V2 = 3.24L

T2 = 58 = 58+273.15 = 331.15K

P1V1/T1 = P2V2/T2

Now, making P2 the subject of the formula,

P2 = P1V1T2/T1V2

P2 = [785 * 2 * 331.15]/[310.15 * 3.24]

P2 = 515.715 Torr

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8 0
3 years ago
When water reaches the metastable state, the phase of water will be?​
Jet001 [13]

Answer:

water, when the metastable state is reached, is cooled below the zero temperature. It freezes abruptly. this is called metastable. They are not at equilibrium per se; as at negative temperatures the only equilibrium state of water is ice.

Explanation:

7 0
3 years ago
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frosja888 [35]

Answer:

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3 years ago
The amount of energy required to heat water for a 10-minute shower (50 gallons) is 2.2125 kJ. How many calories is this?
Zigmanuir [339]
From the problem statement, this is a conversion problem. We are asked to convert from units of kilojoules to units of calories. To do this, we need a conversion factor which would relate the different units involved. We either multiply or divide this certain value to the original measurement depending on what is asked. From literature, we will find that 1 kilojoule is equal to 239 calories. We do as follows:
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2.2125 kJ ( 239 calories / 1 kJ ) = 528.79 calories
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4 years ago
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Setler79 [48]

Answer:

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Explanation:

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For example, consider the elements of Period 3.

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The number of protons increases as you go from one element to the next, but the number of inner electrons is constant.

3 0
3 years ago
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