Molality pertains to a concentration of a mixture expressed in moles of solute per kg of solvent. Based on the given problem, the solute is the phosphoric acid with molecular weight of 97.99 g/mol. Assuming 1 g of sample, the mole of solute is equal to 0.244*(97.99) = 2.49x10-3 moles. The remaining percentage,t that is, 1-0.244 is the amount of solvent, which is equal to 0.756 g based on 1 gram assumption. Therefore, the molality is, (0.244)*(mol/97.99 g)/(1-0.244)*(1 kg/1000 g) = 3.29 molala
Explanation: If three potatoes have mass of 667 g that means that each potato weighs 667/3= 222.33 g (approx) so 100 potatoes must be 100*222.33= 22233 g which equals 22.2 kg because 1 g=1000 kg
