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iris [78.8K]
3 years ago
7

Solve then graph each solution set on a number line 2(w+36)+10>32

Mathematics
1 answer:
goldenfox [79]3 years ago
5 0
Ok the answer to your question is -25
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(-14) - 27 <br> PLEASE HELP ITS FOR A TEST! ASAP PLEASE
alexandr1967 [171]

Answer:

-41

Step-by-step explanation:

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3 years ago
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On a blueprint, the length of a wall is 5 centimeters. If the actual length of the wall is 15 feet, what is the scale of the blu
Yuri [45]

Answer:

1 cm = 3 feet.

Step-by-step explanation:

Divide 15 by 5 to get 3; on the blueprint, every centimeter represents 3 feet.

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3 years ago
There are 10 circles and 2 triangles. What is the simplest ratio of triangles to total shapes?
barxatty [35]

Answer:

1:6

Step-by-step explanation:

Given that there are 10 circles and 2 triangles, the total number of shapes is equal to 10+2.

10+2=12

Because there are 2 triangles, the ratio of triangles to total shapes is equal to 2:12.

However, this ratio can be simplified because both sides are multiples of 2. Divide both sides of the ratio by 2 to simplify the ratio.

2:12

1:6

Therefore, the simplest ratio of triangles to total shapes is 1:6.

I hope this helps!

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3 years ago
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Find the measures of the angles of the triangle whose vertices are A = (-3,0) , B = (1,3) , and C = (1,-3).A.) The measure of ∠A
alekssr [168]

Answer:

\theta_{CAB}=128.316

\theta_{ABC}=25.842

\theta_{BCA}=25.842

Step-by-step explanation:

A = (-3,0) , B = (1,3) , and C = (1,-3)

We're going to use the distance formula to find the length of the sides:

r= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2+(z_1-z_2)^2}

AB= \sqrt{(-3-1)^2+(0-3)^2}=5

BC= \sqrt{(1-1)^2+(3-(-3))^2}=9

CA= \sqrt{(1-(-3))^2+(-3-0)^2}=5

we can use the cosine law to find the angle:

it is to be noted that:

the angle CAB is opposite to the BC.

the angle ABC is opposite to the AC.

the angle BCA is opposite to the AB.

to find the CAB, we'll use:

BC^2 = AB^2+CA^2-(AB)(CA)\cos{\theta_{CAB}}

\dfrac{BC^2-(AB^2+CA^2)}{-2(AB)(CA)} =\cos{\theta_{CAB}}

\cos{\theta_{CAB}}=\dfrac{9^2-(5^2+5^2)}{-2(5)(5)}

\theta_{CAB}=\arccos{-\dfrac{0.62}}

\theta_{CAB}=128.316

Although we can use the same cosine law to find the other angles. but we can use sine law now too since we have one angle!

To find the angle ABC

\dfrac{\sin{\theta_{ABC}}}{AC}=\dfrac{\sin{CAB}}{BC}

\sin{\theta_{ABC}}=AC\left(\dfrac{\sin{CAB}}{BC}\right)

\sin{\theta_{ABC}}=5\left(\dfrac{\sin{128.316}}{9}\right)

\theta_{ABC}=\arcsin{0.4359}\right)

\theta_{ABC}=25.842

finally, we've seen that the triangle has two equal sides, AB = CA, this is an isosceles triangle. hence the angles ABC and BCA would also be the same.

\theta_{BCA}=25.842

this can also be checked using the fact the sum of all angles inside a triangle is 180

\theta_{ABC}+\theta_{BCA}+\theta_{CAB}=180

25.842+128.316+25.842

180

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3 years ago
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andrew-mc [135]

Answer:

\huge \fbox \pink {A}\huge \fbox \green {n}\huge \fbox \blue {s}\huge \fbox \red {w}\huge \fbox \purple {e}\huge \fbox \orange {r}

3x - 2x + 4 = 2 + x + 2 \\ x + 4 = 4 + x \\ x - x = 4 - 4 \\ 0 = 0

•°• LHS = RHS

✏ Hence, proved.

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

\huge\blue{ \mid{ \underline{ \overline{ \tt ꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐ }} \mid}}

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3 years ago
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