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3 years ago

Solve then graph each solution set on a number line 2(w+36)+10>32

Mathematics

1 answer:

goldenfox [79]3 years ago

5 0

Ok the answer to your question is -25

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△TSD ≅ △VRA <br> What is m∠RVA?

NeTakaya

Angle A is 45
Angle R is 72 because S and R are the corresponding angles in the triangle.

To find angle RVA add 72 and 45 and the subtract by 180.

RVA = 180-(72+45) = 63

Hope this helps :)

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4 years ago

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I just don't know how to do it

-BARSIC- [3]

Answer:

Do what exactly? Send a picture or an equation.

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2 years ago

Pls help will give 10 points!

sertanlavr [38]

Answer:

A' (-4, 2)

B' (-4, 4)

C' (-1, 4)

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3 years ago

A particle moves in a straight line so that its velocity at time

riadik2000 [5.3K]

Answer:

s(2) = 7.75

Step-by-step explanation:

given the velocity v(t) = t^3

we can find the position s(t) by simply integrating v(t) and using the boundary conditions s(1)=2

$s(t) = \int {v(t)} \, dt\\ s(t) = \int {t^3} \, dt\\s(t) = \dfrac{t^4}{4}+c$

we know throught s(1) = 2, that at t=1, s =2. we can use this to find the value of the constant c.

$s(1) = \dfrac{1^4}{4}+c\\4 = \dfrac{1^4}{4}+c\\c = 4-\dfrac{1}{4}\\c = \dfrac{15}{4} = 3.75$

Now we can use this value of t to formulate the position function s(t):

$s(t) = \dfrac{t^4}{4}+\dfrac{15}{4}\\$

this is the position at time t.

to find the position at t=2

$s(2) = \dfrac{2^4}{4}+\dfrac{15}{4}\\$

$s(2) = \dfrac{31}{4} = 7.75$

the position of the particle at time, t =2 is s(2) = 7.75

3 0

4 years ago

solve each equation below. check for extraneous solutions. please help and show work because i have no idea how to do this

Naya [18.7K]

Hi Pls find attached file for both solutions

Hope i did not do any calculation mistake:)

4 0

4 years ago