99 POINTS I WILL MARK BRAINILIEST:

Mathematics

2 answers:

agasfer [191]3 years ago

6 0

Given that the perimeter of rhombus ABCD is 20 cm, the length of the sides will be:length=20/4=5 cmthe ratio of the diagonals is 4:3, hence suppose the common factor on the diagonals is x such that:AC=4x and BD=3xusing Pythagorean theorem, the length of one side of the rhombus will be:c^2=a^2+b^2substituting our values we get:5²=(2x)²+(1.5x)²25=4x²+2.25x²25=6.25x²x²=4x=2hence the length of the diagonals will be:AC=4x=4×2=8 cmBD=3x=3×2=6 cmHence the area of the rhombus wll be:Area=1/2(AC×BD)=1/2×8×6=24 cm^2

Andrews [41]3 years ago

6 0

Plz give him brainliest

You might be interested in

According to the rational root theorem, what are all the potential rational roots of f(x)=5x^3-7x+11

Genrish500 [490]

Answer:

$\pm11,\pm1,\pm\frac{11}{5},\pm\frac{1}{5}$

Step-by-step explanation:

The given polynomial function is

$f(x)=5x^3-7x+11$

According to the Rational Roots Theorem, the ratio of all factors of the constant term expressed over the factors of the leading coefficient.

The potential rational roots are

$\pm\frac{11}{1}=\pm11$