4 consecutive integers to equal 2

Alicia has invented a new app that two companies are interested in purchasing for a 2-year contract. Company A is offering $10,0

Fantom [35]

Answer:

Month 8

In this month Company B's plan will pay $64,000 versus $45,000 from Company A.

Step-by-step explanation:

Start by calculating the monthly payments for both plans.

Month - Company A - Company B

1 $10,000 $500

2 $15,000 $1,000

3 $20,000 $2,000

4 $25,000 $4,000

5 $30,000 $8,000

6 $35,000 $16,000

7 $40,000 $32,000

8 $45,000 $64,000

9 $50,000 $128,000

10 $55,000 $256,000

11 $60,000 $512,000

12 $65,000 $1,024,000

13 $70,000 $2,048,000

14 $75,000 $4,096,000

15 $80,000 $8,192,000

16 $85,000 $16,384,000

17 $90,000 $32,768,000

18 $95,000 $65,536,000

19 $100,000 $131,072,000

20 $105,000 $262,144,000

21 $110,000 $524,288,000

22 $115,000 $1,048,576,000

23 $120,000 $2,097,152,000

24 $125,000 $4,194,304,000

7 0

3 years ago

Read 2 more answers

The diameter of a particle of contamination (in micrometers) is modeled with the probability density function f(x)= 2/x^3 for x

natulia [17]

Answer:

a) 0.96

b) 0.016

c) 0.018

d) 0.982

e) x = 2

Step-by-step explanation:

We are given with the Probability density function f(x)= 2/x^3 where x > 1.

<em>Firstly we will calculate the general probability that of P(a < X < b) </em>

P(a < X < b) = $\int_{a}^{b} \frac{2}{x^{3}} dx$ = $2\int_{a}^{b} x^{-3} dx$

= $2[ \frac{x^{-3+1} }{-3+1}]^{b}_a dx$ { Because $\int_{a}^{b} x^{n} dx = [ \frac{x^{n+1} }{n+1}]^{b}_a$ }

= $2[ \frac{x^{-2} }{-2}]^{b}_a$ = $\frac{2}{-2} [ x^{-2} ]^{b}_a$

= $-1 [ b^{-2} - a^{-2} ]$ = $\frac{1}{a^{2} } - \frac{1}{b^{2} }$

a) Now P(X < 5) = P(1 < X < 5) {because x > 1 }

Comparing with general probability we get,

P(1 < X < 5) = $\frac{1}{1^{2} } - \frac{1}{5^{2} }$ = $1 - \frac{1}{25}$ = 0.96 .

b) P(X > 8) = P(8 < X < ∞) = 1/ $8^{2}$ - 1/∞ = 1/64 - 0 = 0.016

c) P(6 < X < 10) = $\frac{1}{6^{2} } - \frac{1}{10^{2} }$ = $\frac{1}{36} - \frac{1}{100 }$ = 0.018 .

d) P(x < 6 or X > 10) = P(1 < X < 6) + P(10 < X < ∞)

= $(\frac{1}{1^{2} } - \frac{1}{6^{2} })$ + (1/ $10^{2}$ - 1/∞) = 1 - 1/36 + 1/100 + 0 = 0.982

e) We have to find x such that P(X < x) = 0.75 ;

⇒ P(1 < X < x) = 0.75

⇒ $\frac{1}{1^{2} } - \frac{1}{x^{2} }$ = 0.75

⇒ $\frac{1} {x^{2} }$ = 1 - 0.75 = 0.25

⇒ $x^{2}$ = $\frac{1}{0.25}$ ⇒ $x^{2}$ = 4 ⇒ x = $2$

Therefore, value of x such that P(X < x) = 0.75 is 2.

8 0

3 years ago

2x - y = 0<br> 4x - y = 0

Delicious77 [7]

Answer:

what's the question here ?

6 0

3 years ago

Read 2 more answers

Identify the linear inequality from the graph

Dovator [93]

Answer:

B) y < 3/4x -2

Step-by-step explanation:

First, to eliminate 2 options let's see what sign we should use. The ≤ is a solid line where < is a dotted line. Next, you need to know which way to flip the sign. If it is under the line it is the < symbol.

5 0

2 years ago

Ticketd to the school play cost $11 for adults and $6 for children. What expression can be used to find the toyal cost for x adu

Makovka662 [10]

Answer:221

Step-by-step explanation:

4 0

3 years ago