Answer:
New force, ![F'=48\times 10^3\ N](https://tex.z-dn.net/?f=F%27%3D48%5Ctimes%2010%5E3%5C%20N)
Explanation:
It is given that,
Force acting between two charged particles, ![F=7.5\times 10^2\ N](https://tex.z-dn.net/?f=F%3D7.5%5Ctimes%2010%5E2%5C%20N)
We need to find the force if they are moved so they are only one-eighth as far apart.
The force between two charged particles separated at a distance of r is given by :
............(1)
If the charges are one-eighth as far apart then, r' =(1/8)r and new force is given by :
..........(2)
Dividing equation (1) and (2) :
![\dfrac{F}{F'}=\dfrac{1}{64}](https://tex.z-dn.net/?f=%5Cdfrac%7BF%7D%7BF%27%7D%3D%5Cdfrac%7B1%7D%7B64%7D)
![F'=7.5\times 10^2\ N\times 64](https://tex.z-dn.net/?f=F%27%3D7.5%5Ctimes%2010%5E2%5C%20N%5Ctimes%2064)
F' = 48000 N
or
![F'=48\times 10^3\ N](https://tex.z-dn.net/?f=F%27%3D48%5Ctimes%2010%5E3%5C%20N)
Hence, this is the required solution.
Answer:
120 m/s
Explanation:
Given:
v₀ = 0 m/s
a = 12 m/s²
t = 10 s
Find: v
v = at + v₀
v = (12 m/s²) (10 s) + 0 m/s
v = 120 m/s
Answer:
Peer Review
Explanation:
When scientist check other scientists the process is dubbed "peer review".