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3 years ago

. Strong language often means

Physics

2 answers:

bearhunter [10]3 years ago

8 0

A. Strong Feelings
The person has knowledge on the topic and feels comfortable expressing the way they feel about it.

san4es73 [151]3 years ago

5 0

I would say that strong language typically reveals strong feelings: strong language would reveal desperation, or very strong feelings: weak feelings would not demand it, and would be more likely accompanied by more controlled behavior.

You might be interested in

The theory of evolution is

tresset_1 [31]

one of several competing scientific models that all seem equally successful in explaining the nature of life on Earth

Explanation:

The theory of evolution is one of the several competing scientific models that all seems to successfully explain the nature of life on earth.
A theory is usually drawn from careful observation of scientific investigation.
Theories generally provides explanation into a phenomenon that occurs in nature.
They are products of careful scientific observations and experiments.
The theory of evolution is but one of them.

Learn more:

Experiments brainly.com/question/5096428

#learnwithBrainly

4 0

3 years ago

William tell must split the apple atop his son's head from a distance of 24 m. when he aims directly at the apple, the arrow is

mezya [45]

Let x = the angle of elevation for shooting the arrow.

Assume
g = 9.8 m/s²
No wind resistance
The vertical launch velocity is 25.1 sin(x) m/s
The horizontal velocity is 25.1 cos(x) m/s

The time of flight is
24/[25.1 cos(x)] s = 0.9562 sec(x) s

Therefore
0.5*[0.9562 sec(x)]*(9.8) = 25.1 sin(x)
4.6854 = 25.1* sin(x)cos(x)
sin(2x) = 0.3733
2x = sin⁻¹ 0.3733 = 21.92 deg
x = 10.96 deg

Answer: 11 degrees (nearest integer)

8 0

4 years ago

Read 2 more answers

Three forces act on an object. Two of the forces have the magnitudes 56 N and 27 N, and make angles 53° and 156°, respectively,

Ludmilka [50]

Answer:

Explanation:

Given

Two forces $F_1$ and $F_2$ at an angle of $\theta _1$ $\theta _2$

$F_1=56\ N$

$F_2=27\ N$

$\theta _1=53^{\circ}$

$\theta _2=156^{\circ}$

As resultant force is zero therefore horizontal component as well as vertical component of force is zero

$\sum F_x=F_1\cos \theta _1+F_2\cos \theta _2+F_3\cos \theta _3$

$\sum F_x=56\cos 53+27\cos 156+F_3\cos \theta$

$F_3\cos \theta_3=-9.035\ N----1$

$\sum F_y=F_1\sin \theta _1+F_2\sin \theta _2+F_3\sin \theta _3$

$F_3\sin \theta _3=55.704\ N----2$

squaring and adding 1 and 2

$F_3^2(\cos ^2\theta _3+\sin^2\theta _3)=86.583+3102.93$

$F_3=56.47\ N$

Divide 1 and 2 to get $\theta _3$

$\frac{\sin \theta_3 }{\cos \theta_3 }=\frac{-55.704}{9.305}$

$\tan \theta_3=-6.16$

$\theta _3=180-80.78$

$\theta _3=99.22^{\circ}$

6 0

3 years ago

You wish to cook some pasta and so take some water and heat it on a stove. If you use 2000 grams of water with an initial temper

Ronch [10]

Answer:

the stove energy went into heating water is 837.2 kJ.

Explanation:

given,

mass of water = 2000 grams

initial temperature = 0° C

Final temperature = 100° C

specific heat of water (c) = 4.186 joule/gram

energy = m c Δ T

= 2000 × 4.186 × (100° - 0°)

= 837200 J

= 837.2 kJ

hence, the stove energy went into heating water is 837.2 kJ.

3 0

3 years ago

A block of mass m 5.00 kg is

vekshin1

<span>a.
the force in the direction of movement
Fx = F x cosA*
Fx = 12 x cos25*
Fx = 10.88
m x a = 10.88
a = 10.88/5
a= 2.18 m/s^2
b.
when the block will be lifted off the floor and when the vertical component
Fy = mg
Fy = F x sin25*
Fy= 5 x 9.8
Fy= 115.94 N
c.
if Fx = ma
a = 115.94/5
a= 23.19 m/s^2
hope it helps
</span>

6 0

3 years ago