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Ilia_Sergeevich [38]
2 years ago
10

Boy or girl and age you can still comment if its answered

Physics
1 answer:
Ksenya-84 [330]2 years ago
6 0

I am a girl and i have a virgina and im 13 tho so dont touch me lolz mark brainly

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Describe the shape of a convex lens and explain what it does to light.
alexira [117]
Convex lenses are thicker at the centers than the edges, they are known as the converging lenses. Rays of light that pass through the lens are brought closer together (they converge). When rays of light that are parallel pass through a convex lens they are refracted, the refracted rays converge at one point called the principal focus. 
4 0
3 years ago
A loaded ore car has a mass of 950 kg. and rolls on rails ofnegligible friction. It starts from rest ans is pulled up a mineshaf
stiks02 [169]

(a) 10241 W

In this situation, the car is moving at constant speed: this means that its acceleration along the direction parallel to the slope is zero, and so the net force along this direction is also zero.

The equation of the forces along the parallel direction is:

F - mg sin \theta = 0

where

F is the force applied to pull the car

m = 950 kg is the mass of the car

g=9.8 m/s^2 is the acceleration of gravity

\theta=30.0^{\circ} is the angle of the incline

Solving for F,

F=mg sin \theta = (950)(9.8)(sin 30.0^{\circ})=4655 N

Now we know that the car is moving at constant velocity of

v = 2.20 m/s

So we can find the power done by the motor during the constant speed phase as

P=Fv = (4655)(2.20)=10241 W

(b) 10624 W

The maximum power is provided during the phase of acceleration, because during this phase the force applied is maximum. The acceleration of the car can be found with the equation

v=u+at

where

v = 2.20 m/s is the final velocity

a is the acceleration

u = 0 is the initial velocity

t = 12.0 s is the time

Solving for a,

a=\frac{v-u}{t}=\frac{2.20-0}{12.0}=0.183 m/s^2

So now the equation of the forces along the direction parallel to the incline is

F - mg sin \theta = ma

And solving for F, we find the maximum force applied by the motor:

F=ma+mgsin \theta =(950)(0.183)+(950)(9.8)(sin 30^{\circ})=4829 N

The maximum power will be applied when the velocity is maximum, v = 2.20 m/s, and so it is:

P=Fv=(4829)(2.20)=10624 W

(c) 5.82\cdot 10^6 J

Due to the law of conservation of energy, the total energy transferred out of the motor by work must be equal to the gravitational potential energy gained by the car.

The change in potential energy of the car is:

\Delta U = mg \Delta h

where

m = 950 kg is the mass

g=9.8 m/s^2 is the acceleration of gravity

\Delta h is the change in height, which is

\Delta h = L sin 30^{\circ}

where L = 1250 m is the total distance covered.

Substituting, we find the energy transferred:

\Delta U = mg L sin \theta = (950)(9.8)(1250)(sin 30^{\circ})=5.82\cdot 10^6 J

8 0
3 years ago
What particle is NOT located in the nucleus? A.proton B.electron C.neutron D.quark
baherus [9]
I think it is electron. Electrons are located outside of the nucleus
5 0
3 years ago
Two Atoms are isotopes of each other if they have the same number of_______ but a different number _________.
zloy xaker [14]
The correct answer is #4. They have the same number of protons but a different number of neutrons.
4 0
3 years ago
What is the identity of a sample that has a volume of 92.5 cm3 and a mass of 249.8 g?
denpristay [2]
Here, We know, Density = Mass / Volume
Here, mass = 249.8 g
volume = 92.5 cm³

Substitute their values, 
d = 249.8 / 92.5
d = 2.7 g/cm³

In short, Your Answer would be "Aluminum" 

Hope this helps!
3 0
3 years ago
Read 2 more answers
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