careful observation, curiosity, logic, creativity, skepticism, and objectivity
The force on the layer will be equivalent to the weight of water on it. This is given by:
F = mg; m is the mass of water and g is the acceleration due to gravity.
The question is incomplete, the complete question is;
Eli states that sodium phosphate is a mixture because it is composed of both sodium ions and phosphate ions. Which is the best analysis of Eli’s statement? It is correct because each ion is a pure substance, so sodium phosphate is made up of two pure substances. It is correct because the composition of sodium phosphate changes depending on the sample. It is incorrect because sodium phosphate is a compound that has a single composition. It is incorrect because the two types of ions in sodium phosphate cannot be seen.
Answer:
It is incorrect because sodium phosphate is a compound that has a single composition
Explanation:
A compound is a neutral substance made up of two or more atoms which are chemically combined together.
Ionic substances are made up of ions. These ions are not separate entities, they are part of the compound.
Hence, Eli's statement is incorrect because sodium phosphate is a compound that has a single composition.
Answer:
A. Area under force-time graph & Area under force-displacement graph
Explanation:
To find the impulse or work done the area under force-time graph and area under force-displacement graph will give us these respective values.
Impulse = Force x time
Work done = Force x displacement
When we plot a graph of force and time, the area under it is the impulse.
When a graph of force and displacement is plotted, the area under is the work done.
Answer:
1196.02 °C
Explanation:
If the kinetic energy is converted into heat,
then,
Kinetic energy of the copper = heat energy of the copper
1/2m(v²) = cm(t₂-t₁)
where m = mass of copper, v = velocity of copper, c = specific heat capacity of copper, t₂ = final temperature of copper, t₁ = initial temperature of copper.
Since the mass of copper remains the same,
1/2v² = c(t₂-t₁)
make t₂ the subject of the equation
t₂ = 1/2(v²/c)+t₁..................... Equation 1
Given: v = 950 m/s, c = 387 J/kg°C, t₁ 30 °C
Substitute into equation 1
t₂ = 1/2(950²/387)+30
t₂ = 1196.02 °C
Hence the temperature the bullet reach before it was stopped = 1196.02 °C
