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3 years ago

What is the period of a soundwave whose wavelength is 20.0 m? Use values from the book and show ALL of your work.

Physics

1 answer:

Liono4ka [1.6K]3 years ago

7 0

<h3>Answer;</h3>

Period = 1/17 seconds

<h3>Explanation;</h3>

Wavelength is related to period by the expression:

speed = wavelength / period 

If we are given the speed, then we can easily calculate the period at the wavelength of 20 m.

Given the speed of sound wave as 340 m/s

Period = Wavelength/ speed

= 20 m/340 m/s

= 1/17 seconds

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The nervous system has two distinct branches. They are the:

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Answer:

central nervous system

peripheral nervous system

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What actions can be explained by physics?

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Всяко действие има равно по големина и противоположно по посока противодействие.

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3 years ago

A block of mass 4 kilograms is initially moving at 5m/s on a horizontal surface. There is friction between the block and the sur

emmasim [6.3K]

• Net vertical force on the block:

∑ F = n - w = 0

(n = magnitude of normal force, w = weight)

n = w = m g

(m = mass, g = 9.8 m/s²)

n = (4 kg) (9.8 m/s²) = 39.2 N

• Net horizontal force:

∑ F = -f = m a

(f = mag. of friction, a = acceleration)

We have f = µ n = 0.5 (39.2 N) = 19.6 N, so

-19.6 N = (4 kg) a

a = -4.9 m/s²

With this acceleration, the block comes to a rest from an initial speed of 5 m/s, so that it travels a distance ∆x in this time such that

0² - (5 m/s)² = 2 (-4.9 m/s²) ∆x

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3 years ago

Maxwell shoots a rubber band at his friend Jimmy. Which type of energy is converted into kinetic energy?

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A stretched rubber band is storing elastic potential energy. (A)

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3 years ago

A wad of clay of mass m1 = 0.49 kg with an initial horizontal velocity v1 = 1.89 m/s hits and adheres to the massless rigid bar

notka56 [123]

Answer:

<h2>The angular velocity just after collision is given as</h2><h2> $\omega = 0.23 rad/s$ </h2><h2>At the time of collision the hinge point will exert net external force on it so linear momentum is not conserved</h2>

Explanation:

As per given figure we know that there is no external torque about hinge point on the system of given mass

So here we will have

$L_i = L_f$

now we can say

$m_1v_1\frac{L}{2} = (m_2L^2 + m_1(\frac{L}{2})^2)\omega$

so we will have

$0.49(1.89)(0.45) = (2.13(0.90)^2 + 0.49(0.45)^2)\omega$

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Linear momentum of the system is not conserved because at the time of collision the hinge point will exert net external force on the system of mass

So we can use angular momentum conservation about the hinge point

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3 years ago