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Gelneren [198K]
2 years ago
7

What is the period of a soundwave whose wavelength is 20.0 m? Use values from the book and show ALL of your work.

Physics
1 answer:
Liono4ka [1.6K]2 years ago
7 0
<h3><u>Answer;</u></h3>

Period = 1/17 seconds

<h3><u>Explanation;</u></h3>
  • Wavelength is related to period by the expression:

<em>speed = wavelength / period </em>

  • If we are given the speed, then we can easily calculate the period at the wavelength of 20 m.

<em>Given the speed of sound wave as 340 m/s </em>

<em>Period = Wavelength/ speed</em>

<em>            = 20 m/340 m/s</em>

<em>            </em><u><em>= 1/17 seconds</em></u>

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Elanso [62]

Answer:

A. The bomb will take <em>17.5 seconds </em>to hit the ground

B. The bomb will land <em>12040 meters </em>on the ground ahead from where they released it

Explanation:

Maverick and Goose are flying at an initial height of y_0=1500m, and their speed is v=688 m/s

When they release the bomb, it will initially have the same height and speed as the plane. Then it will describe a free fall horizontal movement

The equation for the height y with respect to ground in a horizontal movement (no friction) is

y=y_0 - \frac{gt^2}{2}    [1]

With g equal to the acceleration of gravity of our planet and t the time measured with respect to the moment the bomb was released

The height will be zero when the bomb lands on ground, so if we set y=0 we can find the flight time

The range (horizontal displacement) of the bomb x is

x = v.t     [2]

Since the bomb won't have any friction, its horizontal component of the speed won't change. We need to find t from the equation [1] and replace it in equation [2]:

Setting y=0 and isolating t we get

t=\sqrt{\frac{2y_0}{g}}

Since we have y_0=1500m

t=\sqrt{\frac{2(1500)}{9.8}}

t=17.5 sec

Replacing in [2]

x = 688\ m/sec \ (17.5sec)

x = 12040\ m

A. The bomb will take 17.5 seconds to hit the ground

B. The bomb will land 12040 meters on the ground ahead from where they released it

6 0
2 years ago
In some circumstances, it is useful to look at the linear velocity of a point on the blade. The linear velocity of a point in un
mihalych1998 [28]

Answer:

v=wr

Explanation:

<u>Tangent and Angular Velocities</u>

In the uniform circular motion, an object describes the same angles in the same times. If \theta is the angle formed by the trajectory of the object in a time t, then its angular velocity is

\displaystyle w=\frac{\theta}{t}

if \theta is expressed in radians and t in seconds the units of w is rad/s. If the circular motion is uniform, the object forms an angle 2\theta in 2t, or 3\theta in 3t, etc. Thus the angular velocity is constant.

The magnitude of the tangent or linear velocity is computed as the ratio between the arc length and the time taken to travel that distance:

\displaystyle v=\frac{\theta r}{t}

Replacing the formula for w, we have

\boxed{ v=wr}

4 0
3 years ago
Which term describes the time it takes for half of a radioactive elements atoms to decay?
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I think that is half-life
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3 years ago
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Mashutka [201]
The correct answer would be compound
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2 years ago
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