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3 years ago

What is the period of a soundwave whose wavelength is 20.0 m? Use values from the book and show ALL of your work.

Physics

1 answer:

Liono4ka [1.6K]3 years ago

7 0

<h3>Answer;</h3>

Period = 1/17 seconds

<h3>Explanation;</h3>

Wavelength is related to period by the expression:

speed = wavelength / period 

If we are given the speed, then we can easily calculate the period at the wavelength of 20 m.

Given the speed of sound wave as 340 m/s

Period = Wavelength/ speed

= 20 m/340 m/s

= 1/17 seconds

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Another engine reaches its top speed in 7.5s. It is able to perform 250,000 J of wok in that time. How much power this engine ha

EastWind [94]

Answer:

33,333.3J/s

Explanation:

Energy expended which is the work done in Joule

=250,000J

Time taken to expend the energy =7.5s

Power =Unknown

Formula

Power =  Work 

Time

Hence, Power = 250,000J

7.5s

Power = 33,333.3J/s

3 0

3 years ago

a merry go round has a radius of 8 meters makes 2 revolutions every 2.5 minutes. A. express the angular speed of the merry go ar

pantera1 [17]

Answer:

a). $v=83.77x10^{-3} rad/s$

b). $v=0.8$ rpm

c).v=0.5865 m/sec.

Explanation:

Given:

$r=8m$

$v=\frac{2rev}{2.5minutes}$

a).

$2 rev*\frac{2\pirad}{1rev}=4\pi rad$

$t=2.5minutes*\frac{60s}{1minute}=150s$

The angular speed in radians per seconds is

$v=\frac{4\pi}{150s}=83.77x10^{-3} rad/s$

b).

$v=\frac{2rev}{2.5minute}rpm$

$v=0.8$ rpm

Child's distance per revolution

(pi*2r) = 43.988 metres.

v=(43.988 x 0.0133333) = 0.5865 m/sec.

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3 years ago

Vectors a and b have scalar product â6.00, and their vector product has magnitude +9.00. what is the angle between these two vec

salantis [7]

Answer:

Value of angle between vector a and b is $56.30^{\circ}$ .

Explanation:

Vectors a and b have scalar product 6.00

Let $\theta$ be the angle between a and b.

$\vec{a}.\vec{b} = 6$

ab cos $\theta$ = 6 ...(1)

Vectors a and b have magnitude of vector product 9.00

$\vec{a} \times\vec{b} = 9$

ab sin $\theta$ = 9 ...(2)

Dividing equation (2) by (1) we get

$\frac{ab sin \theta}{ab cos \theta} = \frac{9}{6}$

tan $\theta$ = 1.5

$\theta = tan ^{-1} (1.5)$

$\theta$ = $56.30^{\circ}$

Thus, value of angle between vector a and b is $56.30^{\circ}$ .

3 0

4 years ago

In 1991 four English teenagers built an eletric car that could attain a speed of 30.0m/s. Suppose it takes 8.0s for this car to

ivanzaharov [21]

a=Δv/Δt=(30.0-18.0)/8.0=12.0/8.0=1.5 m/s²

6 0

3 years ago

Read 2 more answers

Let A^=6i^+4j^_2k^ and B= 2i^_2j^+3k^. find the sum and difference of A and B

andreyandreev [35.5K]

Explanation:

Let $\textbf{A} = 6\hat{\textbf{i}} + 4\hat{\textbf{j}} - 2\hat{\textbf{k}}$ and $\textbf{B} = 2\hat{\textbf{i}} - 2\hat{\textbf{j}} + 3\hat{\textbf{k}}$

The sum of the two vectors is

$\textbf{A + B} = (6 + 2)\hat{\textbf{i}} + (4 - 2)\hat{\textbf{j}} + (-2 + 3)\hat{\textbf{k}}$

$= 8\hat{\textbf{i}} + 2\hat{\textbf{j}} + \hat{\textbf{k}}$

The difference between the two vectors can be written as

$\textbf{A - B} = (6 - 2)\hat{\textbf{i}} + (4 - (-2))\hat{\textbf{j}} + (-2 - 3)\hat{\textbf{k}}$

$= 4\hat{\textbf{i}} + 6\hat{\textbf{j}} - 5\hat{\textbf{k}}$

8 0

3 years ago