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Gelneren [198K]
3 years ago
7

What is the period of a soundwave whose wavelength is 20.0 m? Use values from the book and show ALL of your work.

Physics
1 answer:
Liono4ka [1.6K]3 years ago
7 0
<h3><u>Answer;</u></h3>

Period = 1/17 seconds

<h3><u>Explanation;</u></h3>
  • Wavelength is related to period by the expression:

<em>speed = wavelength / period </em>

  • If we are given the speed, then we can easily calculate the period at the wavelength of 20 m.

<em>Given the speed of sound wave as 340 m/s </em>

<em>Period = Wavelength/ speed</em>

<em>            = 20 m/340 m/s</em>

<em>            </em><u><em>= 1/17 seconds</em></u>

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A primary advantage of composite materials is: (choose all that apply). 1.) high strength 2.) low weight 3.) ease of constructio
icang [17]

Answer:

primary advantage of composite material are high strength, low weight, corrosion resistance

Explanation:

The primary advantage of composite material is

1) high strength - they are stronger in strength than commanly used material like steel and aluminium.

2)low weight - lighter than most of the material like woods and others metals

3) corrosion resistance - it resist extreme condition of weather and can be good place where handling of chemicals takes place.

4 0
3 years ago
A quantity that has only one magnitude
Len [333]

Answer:

scalar quantity

Explanation:

Vector quantities have two characteristics, a magnitude and a direction. Scalar quantities have only a magnitude.

3 0
3 years ago
melvin pulls a sled across level snow with a force of 317 N along a rope that is 33 degrees above the horizont?
tatuchka [14]

Answer: work Melvin did=9000J

Explanation:

Given to complete the question: If the sled moved 33.9m,how much work did Melvin do? Answer in unit of J and round to the nearest thousandth.

W = F ×S

W = 317 × cos 33°×33.9

W=9012.6055J

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8 0
3 years ago
Ou are driving on the highway at a speed of 40 m/s (which is over the speed limit) when you notice a cop in front of you. To avo
harina [27]

Answer:

What is the acceleration of your vehicle?

+ 2.0 m/s^2✔

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7 0
2 years ago
In a home stereo system, low sound frequencies are handled by large "woofer" speakers, and high frequencies by smaller "tweeter"
Hitman42 [59]

Answer:

C = 2.9 10⁻⁵ F = 29 μF

Explanation:

In this exercise we must use that the voltage is

          V = i X

          i = V/X    

where X is the impedance of the system

in this case they ask us to treat the system as an RLC circuit in this case therefore the impedance is

          X = \sqrt{R^2 + ( wL - \frac{1}{wC})^2 }

tells us to take inductance L = 0.

The angular velocity is

         w = 2π f

the current is required to be half the current at high frequency.

Let's analyze the situation at high frequency (high angular velocity) the capacitive impedance is very small

         \frac{1}{wC} →0       when w → ∞

therefore in this frequency regime

         X₀ = \sqrt{R^2 + ( \frac{1}{2\pi  2 10^4 C} )^2 } =  R  \sqrt{ 1+ \frac{8 \ 10^{-10} }{RC}     }

the very small fraction for which we can despise it

        X₀ = R

to halve the current at f = 200 H, from equation 1 we obtain

         X = 2X₀

let's write the two equations of inductance

          X₀ = R                                    w → ∞

          X= 2X₀ = \sqrt{R^2 +( \frac{1}{wC} )^2 }        w = 2π 200

 

         

we solve the system

         2R = \sqrt{R^2 +( \frac{1}{wC} )^2 }

         4 R² = R² + 1 / (wC) ²

         1 / (wC) ² = 3 R²

          w C = \frac{1}{\sqrt{3} } \ \frac{1}{R}

          C = \frac{1}{\sqrt{3} } \ \frac{1}{wR}

           

let's calculate

           C = \frac{1}{\sqrt{3} } \ \frac{1}{2\pi  \ 200 \ 9}

           C = 2.9 10⁻⁵ F

           C = 29 μF

7 0
3 years ago
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