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Vladimir79 [104]
3 years ago
10

So we were working on some pulley problems but this one has kinda left me scratching my head, please help! My question is for pa

rt C :' )

Physics
1 answer:
USPshnik [31]3 years ago
8 0

Explanation:

(c) I assume we're looking for mA.

Sum of forces on B in the -y direction:

∑F = ma

mBg − T = mBa

Sum of forces on A in the +x direction:

∑F = ma

T = mAa

Substitute:

mBg − mAa = mBa

mBg − mBa = mAa

mA = mB (g − a) / a

Plug in values:

mA = (5 kg) (10 m/s² − 0.01 (10 m/s²)) / (0.01 (10 m/s²))

mA = 495 kg

The answer key seems to have a mistake.  It's possible they meant mB = 1 kg, or they changed mB to 5 kg but forgot to change the answer.

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Answer:

See the explanation below

Explanation:

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density = m/v

where:

density [kg/m^3]

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v = volume [m^3]

If we change the volume of a body by reducing its size, its mass will also decrease proportionally with a density as seen in the equation.

m = density*v

To understand this concept more clearly, let's use the following example:

We know that the density of water is equal to 1000 [kg/m^3], that is, 1 cubic meter of water contains 1000 kilograms of water, using the equation.

1000 = m /1

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3 years ago
How much force is needed to accelerate a 68 kilogram-skier at a rate of 1.2 m/sec^2?
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<span>Answer: Force = 81.6 N

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F = ma --- (1)

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3 years ago
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The first car has twice the mass of a second car, but only half as much kinetic energy. When both cars increase their speed by 9
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Answer:

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Speed of the car 2 =V_2=17.96m/s

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Given:

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mathematically,

M₁ = 2M₂

Kinetic Energy of the car 1 = Half the kinetic energy of the car 2

KE₁ = 0.5 KE₂

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KE =\frac{1}{2}mv^2

where,

m = mass of the body

v = velocity of the body

thus,

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or

\frac{1}{2}2M_2V_1^2=0.5\times \frac{1}{2}M_2V_2^2

or

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or

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