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Vladimir79 [104]
3 years ago
10

So we were working on some pulley problems but this one has kinda left me scratching my head, please help! My question is for pa

rt C :' )

Physics
1 answer:
USPshnik [31]3 years ago
8 0

Explanation:

(c) I assume we're looking for mA.

Sum of forces on B in the -y direction:

∑F = ma

mBg − T = mBa

Sum of forces on A in the +x direction:

∑F = ma

T = mAa

Substitute:

mBg − mAa = mBa

mBg − mBa = mAa

mA = mB (g − a) / a

Plug in values:

mA = (5 kg) (10 m/s² − 0.01 (10 m/s²)) / (0.01 (10 m/s²))

mA = 495 kg

The answer key seems to have a mistake.  It's possible they meant mB = 1 kg, or they changed mB to 5 kg but forgot to change the answer.

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