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True [87]
3 years ago
8

One ordered pair (a,b) satisfies the two equations ab^4 = 12 and a^5 b^5 = 7776. What is the value of 'a' in this ordered pair?

Mathematics
1 answer:
Ivan3 years ago
4 0

Answer:

a = 4.762203156

Step-by-step explanation:

Given:

ab^4 = 12 and a^5b^5 = 7776

Making the equations a subject of a;

a = 12/b^4 and a^5 = 7776/b^5

Finding fifth root on both sides of equation two;

a = \sqrt[5]{7776}/b

You will get a = 6/b

Equating the two equations;

12/b^4 = 6/b

Multiplying both sides by b^4 gives:

b = \sqrt[3]{2} = 1.25992105

We had that a = 12/b^4 so;

a = 12/1.25992105^4 = 12/2.5198421 = 4.762203156

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Polynomial are expressions. The equivalent four-term polynomial of x²+16x+48 is x²+12x+4x+48.

<h3>What are polynomial?</h3>

Polynomial is an expression that consists of indeterminates(variable) and coefficient, it involves mathematical operations such as addition, subtraction, multiplication, etc, and non-negative integer exponentials.

In order to find the equivalent four-term polynomial of the given quadratic equation, we will break constant b(16) into two parts such that the sum of the parts is 16, while their product is equal to the product of the constant a(1) and c(48).

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