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igomit [66]
3 years ago
6

11. Are (triangle) ABC and (triangle) CDA congruent? Justify your answer.

Mathematics
1 answer:
Oliga [24]3 years ago
4 0
Yes they are both of the sizes are the same
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HELP ME PLEASE !!<br> Determine whether the relation is a function. Explain.
GarryVolchara [31]

Answer: Yes, The relation is a function, they are the exact opposite.

Step-by-step explanation:

8 0
3 years ago
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Find the radius of a circle whose circumference is 31.4 centimeters. Approximate Π as 3.14.
sladkih [1.3K]

The circumference of every circle is   (pi) times (diameter).

The diameter is (2 x radius), so we can write

                  Circumference = (pi) x (2 x radius) .

The question gives us the circumference, and the number to use for (pi).
I shall now pluggum in:

                  (31.4 cm)  =  (3.14) x (2 x radius)

Divide each side by  3.14:       (31.4 cm)/(3.14)  =  2 x radius

Divide each side by 2 :            (31.4 cm) / (2 x 3.14)  =  radius

                                                             5 cm  =  radius 
8 0
3 years ago
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I need help on this it’s about trig identities
Cerrena [4.2K]

Answer:

The answer to your question is:

Step-by-step explanation:

1.-

\frac{1 + sin\alpha }{cos\alpha } + \frac{cos\alpha }{1 + sin\alpha } = 2 sec\alpha

\frac{(1 + sin\alpha)^{2} + cos^{2} \alpha  }{cos\alpha (1 + sin\alpha) }

\frac{1  + 2sin\alpha + sin^{2} \alpha+ cos^{2} \alpha  }{cos\alpha + sin\alphacos\alpha  }

\frac{2 + 2sin\alpha }{cos\alpha+ sin\alpha cos\alpha  }

\frac{2(1 + sin\alpha) }{cos\alpha(1 + sin\alpha ) }

\frac{2}{cos\alpha }

2sec\alpha

2.-

   sec²x - tanxsecx

\frac{1}{cos^{2}x } - \frac{sinx}{cosx} \frac{1}{cosx}

\frac{1}{cos^{2} x} - \frac{sinx}{cos^{2}x}

\frac{1 - sinx}{cos^{2}x }

\frac{1 - sinx}{1 - sin^{2}x }

\frac{1 - sinx}{(1 - sinx)(1 + sinx)}

\frac{1}{1 + sinx}

3 0
3 years ago
Chris has been hired to assess a new version of a college entrance exam. He randomly assigns 100 high school juniors to take the
balu736 [363]

Answer:

Internal validity

Step-by-step explanation:

The internal validity here is weak

Internal validity describes the extent to which an evidence weighs the cause and effect claim. In this study, the internal validity that brought about failure in the new exam is mainly due to the environment where the exam was written and not the new exam itself.

So this validity is weak in claiming that the new exam is not a good substitute for the old exam.

Putting them in the same good environment might help the researchers to draw a better conclusion.

7 0
3 years ago
Find the solution set of the system of equations below y=1/2x-1 and x+y=4
DerKrebs [107]
I hope this helps you

4 0
3 years ago
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