The engine ran for 10 second
You must use 134 g O₂ to produce 118 g H₂O.
M_r: 32.00 18.02
2H₂ + O₂ ⟶ 2H₂O
Moles of H₂O = 150.9 g H₂O × (1 mol H₂O/18.02 g H₂O) = 8.374 mol H₂O
Moles of O₂ = 8.374 mol H₂O × (1 mol O₂/2 mol H₂O) = 4.187 mol O₂
Mass of O₂ = 4.1877 mol O₂ × (32.00 g O₂/1 mol O₂) = 134 g O₂
C) a fundamental force would be gravity
Answer:
H2O < NH3 < CCl4 < BCl3
Explanation:
Bond angle of a molecule or an ion can be explained by two concepts which are either by their valence shell electron pair repulsion (VSEPR) model or hybridization.
The VSEPR model determines the total number of electron pairs surrounding the central atom of the species. All the electron pairs will orient themselves in such a way as to minimize the electrostatic repulsions between them. These repulsions hence determine the geometry of the covalent bond angles around the central atom.
Hence; as the number of lone pairs increases from zero to 2 the bond angles diminish progressively.
Hybridization is the mixing and blending of two or more pure atomic orbitals to form two or moe hybrid atomic orbitals which are identical in shape and energy. During the process of formation of these hybrid orbitals, The bonds formed i.e the sigma bond and the pi bond determines the bond angle of such compound.
From the given compounds;
H20 have a bond angle of 104.5°
NH3 have a bond angle of 107°
BCl3 have a bond angle of 120°
CCl4 have a bond angle of 109.5°
thus in an increasing order of bond angle:
H2O < NH3 < CCl4 < BCl3
Closest to Mg: Neon Must lose 2 electrons?
Closest to S: Argon Must gain 2 electrons?
I know the noble gases are right, but I'm not 100% sure if you just need to add/subtract electrons.
