Question

A solution of H 2 SO 4 ( aq ) with a molal concentration of 1.66 m has a density of 1.104 g / mL . What is the molar concentration of this solution?

Answer 1

Answer:

1.58 M

Explanation:

$H_2SO_4$ is 1.66 m concentration.

Which means that 1.66 moles of  $H_2SO_4$ are present in 1 kg of the solvent, water.

Mass of water = 1 kg = 1000 g

Moles of $H_2SO_4$ = 1.66 moles

Molar mass of $H_2SO_4$ = 98.079 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$1.66\ mole= \frac{Mass}{98.079\ g/mol}$

$Mass_{H_2SO_4}= 162.81114\ g$

Total mass = 1000 g + 162.81114 g = 1162.81114 g

Density = 1.104 g/mL

Volume of the solution = Mass / Density = 1162.81114 / 1.104 mL = 1053.27 mL = 1.05327 L

Considering:-

Molarity = moles/ Volume of solution = 1.66 / 1.05327 M = 1.58 M