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Juliette [100K]
3 years ago
5

A 50 W engine generates 50 J of energy. How long did it run for?

Chemistry
2 answers:
Ivanshal [37]3 years ago
7 0

Answer:  A  Explanation:

Inessa [10]3 years ago
6 0
The engine ran for 10 second
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What is the tyndall effect
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Answer: Tyndall effect is the scattering of light due dispersed colloidal particles that does not settle in a solution. Colloidal particles constantly moves because of Brownian motion and blocks or hinders light particles to pass through. Colloidal particles are medium sized particles but smaller enough than suspension.

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What does towels represents on earth?
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Which element has exactly five electrons in the highest principal energy level (the outer shell)?
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4 years ago
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A mixture of CO2 and Kr weighs 35.0 g and exerts a pressure of 0.708 atm in its container. Since Kr is expensive, you wish to re
ollegr [7]

Explanation:

Since, it is given that carbon dioxide is completely removed by absorption with NaOH. And, pressure inside the container is 0.250 atm.

For Kr = 0.250 atm and pressure CO_{2} will be calculated as follows.

           CO_{2} = (0.708 - 0.250) atm

                       = 0.458 atm

Now, we will calculate the mole fraction as follows.

            CO_{2} = \frac{0.458}{0.708}

                       = 0.646

               Kr = \frac{0.250}{0.708}

                    = 0.353

Now, we will convert into gram fraction as follows.

              CO_{2} = 0.646 \times 44

                          = 28.424

                   Kr = 0.353 \times 83.78

                        = 29.57

Therefore, total mass is calculated as follows.

           Total mass = (28.424 + 29.57)

                              = 57.994

Hence, the percentage of CO_{2} and Kr are calculated as follows.

          CO_{2} = \frac{28.424}{57.99} \times 100

                     = 49%

               Kr = \frac{29.57}{57.99} \times 100

                    = 51%

Hence, amount of CO_{2} and Kr present i mixture is as follows.  

         CO_{2} in mixture = 35 \times 0.49

                             = 17.15 g

                  Kr = 35 \times 0.51

                       = 17.85 g

Thus, we can conclude that 17.15 g of CO_{2} is originally present and 17.85 g of Kr is recovered.

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3 years ago
PLEASE MY TEACHER DIDNT TEACH ME THIS PLEASE
allsm [11]

A. group 1.

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