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3 years ago

Dan said that if a quadratic equation does not have any real solutions , it is not a function . Critique his reasoning

1 answer:

8 0

<span> Solutions of a quadratic functions are x-intercepts, or when y equals zero. A graph with its maximum (highest point) below the x-axis or a graph with its minimum (lowest point) above the x-axis never touches or crosses the x-axis, so it has no real solutions. It is still a quadratic function, as long as it has a variable to the second power (definition of quadratic) and passes the vertical line test (definition of function).

Hope this helped! <3

</span>

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Valentina's least favorite weekly chore is mowing the lawn, even though it only takes her about 30 minutes. Her

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3 years ago

Original price: $55 Discount: Sale Price $46.75

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Answer:

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Discount percentage:

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3 years ago

It costs $0.60 per ft² to cover a right triangular field with sod. The side lengths of the field are 300 ft, 400 ft, and 500 ft.

algol [13]

In this triangle, we know base & perpendicular are 300 & 400 'cause 500 is the longest side which is hypotenuse

Now, Area of a triangle = ab/2 = (300)(400)/2 = 120000/2 = 60000

As cost for 1 ft² = $0.60
cost for 60000 ft² = 60000 * 0.60 = $36000

In short, Your Answer would be Option A

Hope this helps!

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4 years ago

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slavikrds [6]

X^+5x would be the answer

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3 years ago

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The cost of a circular table is directly proportional to the square of the radius. A circular table with a radius of 50cm costs

Lana71 [14]

Answer:

£135 is the correct answer.

Step-by-step explanation:

Let C be the cost of table.

And let R be the radius of table.

Cost of table is directly proportional to square of radius.

As per question statement:

$C\propto R^{2}$ or

$C=a\times R^2 ....... (1)$

where $a$ is the constant to remove the $\propto sign$ .

It is given that

$C_1 =$ £60 and $R_1 = 50\ cm$

$C_2 = ?$ when $R_2= 75\ cm$

Putting the values of $C_1$ and $R_1$ in equation (1):

$60=a \times 50^2 ....... (2)$

Putting the values of $C_2$ and $R_2$ in equation (1):

$C_2=a \times 75^2 ....... (3)$

Dividing equation (2) by (3):

$\dfrac{60}{C_2}= \dfrac{a \times 50^2}{a \times 75^2}\\\Rightarrow \dfrac{60}{C_2}= \dfrac{50^2}{75^2}\\\Rightarrow \dfrac{60}{C_2}= \dfrac{2^2}{3^2}\\\Rightarrow \dfrac{60}{C_2}= \dfrac{4}{9}\\\Rightarrow C_2 = 15 \times 9 \\\Rightarrow C_2 = 135$

So, <em>£135 is the correct answer</em>.

7 0

3 years ago