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zimovet [89]
2 years ago
11

Five friends each knit one part of a scarf that is 11 yards long. 12 Which shows the fractions of the scarf each friend could ha

ve knit?
HELP HELP FAST​
Mathematics
1 answer:
kotegsom [21]2 years ago
3 0

Answer:

2/12 + 3/12 + 3/12 + 2/12 + 5/12

Step-by-step explanation:

I hope I'm right

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Solve the binomial (5x+1)^2​
Lorico [155]

Answer:

x=-1/5

double zero

Step-by-step explanation:

(5x+1)(5x+1)

x=-1/5

double zero

5 0
2 years ago
solve the inequality below. Use the drop-down menus to describe the solution and its graph -7x+13>41
3241004551 [841]

。☆✼★ ━━━━━━━━━━━━━━  ☾  

-7x + 13 > 41

- 13

-7x > 28

/ -7

x < -4

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7 0
3 years ago
60 is 25% of what number?
Marysya12 [62]
Your answer would be 15. You first would move the "pretend" decimal to the left 2 times. so it would end up being 0.25. So then you would set up your problem. 0.25 x 60 =. Which should give you the answer of 15.
5 0
3 years ago
Read 2 more answers
What is the surface area of this right rectangular prism?
vagabundo [1.1K]

Answer:

A≈32\frac{3}{10}ft²

--

To find the surface area of a right rectangular prism you must use this formula A=2(wl+hl+hw)

Then plug in your variebles

A=2( 1.33*1.5+5+1.5+5+1.33)

This comes out to be A≈32 \frac{3}{10}

4 0
2 years ago
Given the recursive function f(n) = f(n - 1) - 3 ; f(1) = 9 , what would be the first three terms of the sequence ?
Ann [662]

The first three terms of sequence are 9 , 6 , 3

<em><u>Solution:</u></em>

Given the recursive function f(n) = f(n - 1) - 3

Where f(1) = 9

To find: First three terms of sequence

Substitute n = 2 , n = 3 and n = 4 in given recursive function

When n = 2

f(n) = f(n - 1) - 3

f(2) = f(2 - 1) - 3

f(2) = f(1) - 3

f(2) = 9 - 3 = 6

f(2) = 6

Thus second term is 6

When n = 3

f(3) = f( 3 - 1) - 3

f(3) = f(2) - 3

f(3) = 6 - 3 = 3

f(3) = 3

Thus the third term is 3

When n = 4

f(4) = f( 4 - 1) - 3

f(4) = f(3) - 3

f(4) = 3 - 3

f(4) = 0

Thus the fourth term is 0

Thus first three terms of sequence are 9 , 6 , 3

6 0
3 years ago
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