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2 years ago

Find c such that (−3,−8), (−7,−6), and (c,4) lie on a line.

1 answer:

7 0

If the 3 points are collinear, then the slopes of all line segments connecting the points are the same.

Thus,

-6 - (-8) 2
m = ------------- = -------- = -1/2
-7 - (-3) -4

Then the following must be true:

4-(-6) 10
-1/2 = ------------ = ---------
c - (-7) c + 7

Cross multiplying, -(c+7) = 20, and c+7 = -20, so that c = -27

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The employees of a hardware store ordered lunch from a local delicatessen. The lunch consisted of 4 turkey sandwiches and 7 orde

AleksandrR [38]

Answer:

Charges of Turkey is $6.25

Charges of French Fries is $1.90

Step-by-step explanation:

Given

Represent Turkeys with T and French Fries with F;

$4T + 7F = 38.3$

$5T + 5F = 40.75$

Required

Determine the values of T and F

$5T + 5F = 40.75$

Divide through by 5

$T + F = 8.15$

Make F the subject

$F = 8.15 - T$

Substitute 8.15 - T for F in the first equation

$4T + 7F = 38.3$

$4T + 7(8.15 - T) = 38.30$

$4T + 57.05 - 7T = 38.30$

Collect Like Terms

$4T - 7T = 38.30 - 57.05$

$-3T = -18.75$

Solve for T

$T = -18.75/-3$

$T = 6.25$

Recall that:

$F = 8.15 - T$

$F = 8.15 - 6.25$

$F = 1.90$

6 0

2 years ago

Please helpppp to find the answer would really appreciate it !

son4ous [18]

Answer:

the answer is in the attachment

4 0

2 years ago

Consider the initial value function y given by

Nuetrik [128]

Answer:

y(s) = $\frac{5s-53}{s^{2} - 10s + 26}$

we will compare the denominator to the form $(s-a)^{2} +\beta ^{2}$

$s^{2} -10s+26 = (s-a)^{2} +\beta ^{2} = s^{2} -2as +a^{2} +\beta ^{2}$

comparing coefficients of terms in s

$s^{2} :$ 1

s: -2a = -10

a = -2/-10

a = 1/5

constant: $a^{2}+\beta ^{2} = 26$

$(\frac{1}{5} )^{2} + \beta ^{2} = 26\\\\\beta^{2} = 26 - \frac{1}{10} \\\\\beta =\sqrt{26 - \frac{1}{10}} =5.09$

hence the first answers are:

a = 1/5 = 0.2

β = 5.09

Given that y(s) = $A(s-a)+B((s-a)^{2} +\beta ^{2} )$

we insert the values of a and β

$\\5s-53$ = $A(s-0.2)+B((s-0.2)^{2} + 5.09^{2} )$

to obtain the constants A and B we equate the numerators and we substituting s = 0.2 on both side to eliminate A

5(0.2)-53 = A(0.2-0.2) + B((0.2-0.2)²+5.09²)

-52 = B(26)

B = -52/26 = -2

to get A lets substitute s=0.4

5(0.4)-53 = A(0.4-0.2) + (-2)((0.4 - 0.2)²+5.09²)

-51 = 0.2A - 52.08

0.2A = -51 + 52.08

A = -1.08/0.2 = 5.4

the constants are

a = 0.2

β = 5.09

A = 5.4

B = -2

Step-by-step explanation:

since the denominator has a complex root we compare with the standard form $s^{2} -10s+26 = (s-a)^{2} +\beta ^{2} = s^{2} -2as +a^{2} +\beta ^{2}$
Expand and compare coefficients to obtain the values of a and β as shown above
substitute the values gotten into the function
Now assume any value for 's' but the assumption should be guided to eliminate an unknown, just as we've use s=0.2 above to eliminate A
after obtaining the first constant, substitute the value back into the function and obtain the second just as we've shown clearly above

Thanks...

3 0

2 years ago

Which of the following is one branch or part of the government?

baherus [9]

Answer:

Congress

Step-by-step explanation:

6 0

2 years ago

Kendall is solving this inequality. x/2 + 6 > 42 What should she do first to solve?

Aleonysh [2.5K]

Answer:

see below

Step-by-step explanation:

First, she should subtract 6 from both sides of the inequality. This makes it so that the x terms are on one side and the non-x terms are on the other side so she can then solve for x by multiplying the entire inequality by 2.

3 0

3 years ago