Answer:
it 5.5⋅10−^8m
Step-by-step explanation:
Unless I'm missing something important here, you can find the difference between the two wavelengths by subtracting one from the other. Since you're interested in finding how much longer the wavelength associated with the orange light is, subtract the wavelength of the green light from the wavelength of the orange light. You know that the two measured wavelengths are 6.15 ⋅ 10 − 7 m → orange light 5.6 ⋅ 10 − 7 m → green light Therefore, the difference between the two wavelengths will be Δ wavelength = 6.15 ⋅ 10 − 7 m − 5.6 ⋅ 10 − 7 m = 5.5 ⋅ 10 − 8 m
Yeah I don’t know yeah I don’t know why you don’t like it but I’m not a
Okay. Handle 500-100 first. That brings it to 3{5[10+5(400)+399]}. Next, Handle 5(400). That brings you to 3{5{10+2,000+399]}. Then handle all the addition. That leads to 3[5(2,409)]. Next, configure 5(2409). That leads to 3(12045). Then do that one which ends as 36,135 for a final answer.
Answer:
The optimal, vertex, value will be a minimum
Step-by-step explanation:
The given zeros of the quadratic relation are 3 and 3
The sign of the second differences of the quadratic relation = Positive
Whereby the two zeros are the same as x = 3, we have that the point 3 is the optimal value or vertex (the repeated point in the graph of the quadratic relation) of the quadratic relation
Whereby, the table of values for the quadratic relation from which the second difference is found starts from x = 3, we have;
To the right of the coordinate points of the zeros of the quadratic relation, the positive second difference in y-values gives as x increases, y increases which gives a positive slope
By the nature of the quadratic graph, the slope of the line to the left of the coordinate point of the zeros of the quadratic relation will be of opposite sign (or negative). The quadratic relation is cup shaped and the zeros, therefore, the optimal value will be a minimum of the quadratic relation
<span>3x^2 + 16x + 9 −16x − 12
= 3x^2 - 3
hope it helps</span>
