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ohaa [14]
3 years ago
10

Find c such that (−3,−8), (−7,−6), and (c,4) lie on a line.

Mathematics
1 answer:
bearhunter [10]3 years ago
7 0
If the 3 points are collinear, then the slopes of all line segments connecting the points are the same.

Thus,

-6 - (-8) 2
m = ------------- = -------- = -1/2
-7 - (-3) -4

Then the following must be true:

4-(-6) 10
-1/2 = ------------ = ---------
c - (-7) c + 7

Cross multiplying, -(c+7) = 20, and c+7 = -20, so that c = -27
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PLEASE HELP IM DESPERATE WILL GIVE BRAINLIEST ONLY ANSWER IF YOU ARE HELPING
VARVARA [1.3K]

Answer:

48

Step-by-step explanation:

u • w

= (i + 6j ) • (9i - 2j )

= (1 × 9 ) + (6 × - 2 )

= 9 + (- 12)

= 9 - 12

= - 3

v • w

= (5i - 3j ) • (9i - 2j )

= (5 × 9) + (- 3 × - 2)

= 45 + 6

= 51

Then

u • w + v • w

= - 3 + 51

= 48

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3 years ago
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agasfer [191]
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7 0
3 years ago
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Complete the recursive formula of the geometric sequence -0.56\,,-5.6\,,-56\,,-560,...−0.56,−5.6,−56,−560,...Minus, 0, point, 56
pentagon [3]

Answer:

The recursive formula is:

Cn = 10C(n-1)

Step-by-step explanation:

Given the geometric sequence.

-0.56, -5.6, -56, -560, ...

The common ratio is

-5.6/-0.56 = -56/-5.6 = -560/-56 = ... = 10

The recursive formula is easily

Cn = C(n-1) × 10

That is a number is ten times the preceding number.

7 0
3 years ago
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