How do you simplify i256? what is i256 simplified?

Reflect the image over the y-axis and then translate 8 units down. What are the coordinates for C’?

irakobra [83]

Answer:

(-7, -7)

Step-by-step explanation:

1. Let's ONLY focus on point C.

2. The algebraic rule for reflecting across the y-axis is (x, y) -> (-x, y).

Since point C is on the coordinate (7,1), when reflecting it across the y-axis, it's going to turn into (-7,1).

3. The algebraic rule for translating 8 units down is (x, y) -> (x, y - 8).

Since C is on (-7,1), when we translate it 8 units down, we'll get C' as (-7, -7)

Therefore, the coordinates for C' are (-7, -7).

3 0

3 years ago

According to monetary theory, which of the following is the main driver in changing economic activity?

Dennis_Churaev [7]

Answer:

B

Step-by-step explanation:

money supply because this has to balanced out in turn will determine any change in the economic activity.

5 0

3 years ago

Kaitlin wants to pour 27.17 grams of salt into a container. So far, she has poured 25.98 grams. How much more salt should Kaitli

LekaFEV [45]

Answer:

1.19

Step-by-step explanation:

27.17-25.98= 1.19

5 0

3 years ago

Which of the following lists is in order from smallest to largest?

Stells [14]

Answer:

The following list is in order from smallest to largest is $17\%,0.175,\frac{2}{11},\frac{1}{5}$

Step-by-step explanation:

Let the numbers be $\frac{2}{11},\frac{1}{5},17\%,0.175$

To find the list in order from smallest to largest:

$\frac{2}{11},\frac{1}{5},17\%,0.175$

Rewritting the above numbers as below

$0.18,0.5,\frac{17}{100},0.175$

$0.18,0.5,0.17,0.175$

Now arranging the numbers in order from smallest to largest

$0.17,0.175,0.18,0.5$

$\frac{17}{100},0.175,\frac{2}{11},\frac{1}{5}$

The arranged numbers can be written as

$17\%,0.175,\frac{2}{11},\frac{1}{5}$

The following list is the order from smallest to largest is $17\%,0.175,\frac{2}{11},\frac{1}{5}$

5 0

3 years ago

Write the vector u as a sum of two orthogonal vectors, one of which is the vector projection of u onto v, proj,u

11Alexandr11 [23.1K]

Answer:

Take $b = \frac{-17}{25}(7,1)$ as the projection of u onto v and $w \frac{1}{25}(-31,217)$ as the vector such that b+w =u

Step-by-step explanation:

The formula of projection of a vector u onto a vector v is given by

$\frac{u\cdot v}{v\cdot v}v$ , where $cdot$ is the dot product between vectors.

First, let b ve the projection of u onto v. Then

$b = \frac{u\cdot v}{v\cdot v}v= \frac{-6\cdot 7+8\cdot 1}{7\cdot 7+1\cdot 1}(7,1) = \frac{-34}{50}(7,1) = \frac{-17}{25}(7,1)$

We want a vector w, that is orthogonal to b and that b+w = u. From this equation we have that w = u-b = (-6,8)-\frac{-17}{25}(7,1)= \frac{1}{25}(-31,217)[/tex]

By construction, we have that w+b=u. We need to check that they are orthogonal. To do so, the dot product between w and b must be zero. Recall that if we have vectors a,b that are orthogonal then for every non-zero escalar r,k the vector ra and kb are also orthogonal. Then, we can check if w and b are orthogonal by checking if the vectors (7,1) and (-31, 217) are orthogonal.

We have that $(7,1)\cdot(-31,217) = 7\cdot -31 + 217 \cdot 1 = -217+217 =0$ . Then this vectors are orthogonal, and thus, w and b are orthogonal.

5 0

3 years ago