We have been given in a cohort of 35 graduating students, there are three different prizes to be awarded. We are asked that in how many different ways could the prizes be awarded, if no student can receive more than one prize.
To solve this problem we will use permutations.
We know that formula for permutations is given as
On substituting the given values in the formula we get,
Therefore, there are 39270 ways in which prizes can be awarded.
*) 2/4+3i
2+3i
I'm not sure is that right or wrong
Answer: You would get 1 for the first section
Step-by-step explanation: you square whatever number is the x then you cube the x.
Answer:
Circumference = 10π
Step-by-step explanation:
First identify the circumference formula as such:
2πr (where r ⇒ radius, π ⇒ pi)
Knowing 2 times the radius (2r) in the formula can be rewritten as the diameter, the formula itself can be rewritten as:
πd (where d ⇒ diameter, π ⇒ pi)
If we know the diameter = 10 inches, substitute in the circumference formula πd to get:
π * 10 inches = 10 * π inches = 10π inches
It is D i hopes this helped like plz
