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insens350 [35]
3 years ago
9

5 STARS!! What is the exact value of x? 4·6^3x=221

Mathematics
1 answer:
larisa [96]3 years ago
8 0
A,x=
log(55.25)  \div 3 log(6)
=0.7464,by the way
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I need help please help me
Elan Coil [88]
Here’s the correct answer and how I got it :)

6 0
3 years ago
Read 2 more answers
VERY URGENT HAVE A TEST TO TAKE
Daniel [21]
The easiest way is to try the point (-4,1), that is, x=-4, y=1,
to see which equation works.
b works.

The usual way to do it is to find the equation of the circle
standard form of a circle is (x-h)²+(y-k)²=r², (h,k) are the coordinates of the center, r is the radius. 
in this case, the center is (-2,1), so (x+2)²+(y-1)²=r²
the given point (-4,1) is for you to find r: (-4+2)²+(1-1)²=r², r=2
so the equation is (x+2)²+(y-1)²=2² 
expand it: x²+4x+4+y²-2y+1=4
x²+y²+4x-2y+1=0, which is answer b.

5 0
3 years ago
Rewrite the radical exponent as a radical
shepuryov [24]
\bf a^{\frac{ n}{ m}} \implies  \sqrt[ m]{a^ n} 
\qquad \qquad
\sqrt[ m]{a^ n}\implies a^{\frac{ n}{ m}}\\\\
-------------------------------\\\\
\left( 5^{\frac{3}{4}} \right)^{\frac{2}{3}}\implies 5^{\frac{3}{4}\cdot \frac{2}{3}}\implies 5^{\frac{1}{2}}\implies \sqrt[2]{5^1}\implies \sqrt{5}
3 0
3 years ago
A shopkeeper buys two types of tea one at $20 for 10 kg and the other at $23 for 10 kg. He mixes the two types and the mixture i
lorasvet [3.4K]
Let us take the case of first type of tea
Cost of 10 kg of tea one = $20
Then
Cost of 1 kg of tea one = (20/10) dollars
                                     = 2 dollars
Now let us take the case of the second kind of tea
Cost of 10 kg of tea = $23
Then
Cost of 1 kg of tea = (23/10) dollars
                               = 2.3 dollars
So
The mixture of 1 kg of tea one
and 1 kg of second type of tea will cost = (2.0 + 2.3) dollars
                                                                = 4.3 dollars
Then the cost of 2kg mixture of tea costs = 4.3 dollars
So
The cost of 10 kg mixture will cost = (4.3/2) * 10 dollars
                                                         = 4.3 * 5 dollars
                                                        = 21.5 dollars
Then
The amount of profit made by selling 10 kg tea at $38 = (38 - 21.5) dollars
                                                                                       = 16.5 dollars
So
Percentage of profit made = (16.5/21.5) * 100
                                           = 1650/21.5
                                           = 76.74 percent
So the percentage of profit made is 76.74%.
3 0
3 years ago
Twenty pounds of a salt-water solution contains fifteen percent salt. How much salt is in the water?
SVETLANKA909090 [29]
It is 15% of 20 pound water
15/100x20
3lb
5 0
3 years ago
Read 2 more answers
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