Answer:
The length of each side is 26.3 cm
Step-by-step explanation:
Opposite sides of an isoceles triangle are equal
The isoceles triangle is divided into 2 right-angled triangles so the length of one side can be calculated using trigonometric ratio
When the isoceles triangle is divided, the angle in the right-angled triangle is 20° (1/2 of 40°) and the base is 9cm (1/2 of 18 cm), the hypotenuse side is calculated using trigonometric ratio
Let the length of the hypotenuse side be y
9/y = sin 20°
y = 9/0.3420 = 26.3
Length of each side is 26.3 cm
<h3>Given</h3>
tan(x)²·sin(x) = tan(x)²
<h3>Find</h3>
x on the interval [0, 2π)
<h3>Solution</h3>
Subtract the right side and factor. Then make use of the zero-product rule.
... tan(x)²·sin(x) -tan(x)² = 0
... tan(x)²·(sin(x) -1) = 0
This is an indeterminate form at x = π/2 and undefined at x = 3π/2. We can resolve the indeterminate form by using an identity for tan(x)²:
... tan(x)² = sin(x)²/cos(x)² = sin(x)²/(1 -sin(x)²)
Then our equation becomes
... sin(x)²·(sin(x) -1)/((1 -sin(x))(1 +sin(x))) = 0
... -sin(x)²/(1 +sin(x)) = 0
Now, we know the only solutions are found where sin(x) = 0, at ...
... x ∈ {0, π}
We need to find the expression for " number_of_prizes is divisible number_of_participants". Also there should not remain any remainder left. On in order words, we can say the reaminder we get after division is 0.
Let us assume number of Prizes are = p and
Number of participants = n.
If we divide number of Prizes by number of participants and there will be not remainder then there would be some quotient remaining and that quotent would be a whole number.
Let us assume that quotent is taken by q.
So, we can setup an expression now.
Let us rephrase the statement .
" Number of Prizes ÷ Number of participants = quotient".
p ÷ n = q.
In fraction form we can write
p/n =q ; n ≠ 0.
