We are given two relations
(a)
Relation (R)
![R=[((k-8.3+2.4k),-5),(-\frac{3}{4}k,4)]](https://tex.z-dn.net/?f=R%3D%5B%28%28k-8.3%2B2.4k%29%2C-5%29%2C%28-%5Cfrac%7B3%7D%7B4%7Dk%2C4%29%5D)
We know that
any relation can not be function when their inputs are same
so, we can set both x-values equal
and then we can solve for k
............Answer
(b)
S = {(2−|k+1| , 4), (−6, 7)}
We know that
any relation can not be function when their inputs are same
so, we can set both x-values equal
and then we can solve for k
Since, this is absolute function
so, we can break it into two parts
we get
so,
...............Answer
Answer:
15
Step-by-step explanation:
plug it into a calculator and u get 15 its very simple
Hey there! :)
Answer:
(3.5, -1).
Step-by-step explanation:
Use the midpoint formula to solve this problem:
Plug in the coordinates given:
Simplify:
Therefore, the coordinates of the mid-point are:
(3.5, -1).
Answer:
390.8 ft2 I think
Step-by-step explanation:
Answer:
yes.
Step-by-step explanation:
to find this answer, use the pythagoras theorem. the pythagoras theorem states that a² + b² = c².
to see if this is a right angled triangle, we will use this formula, as the pythagoras theorem only works for right angled triangles.
we are going to work out c, which is always the hypotenuse. the hypotenuse is the longest side of a triangle, that is larger than the other values. we know that the hypotenuse of this triangle is 17, so let’s see if that’s the answer we get.
calculation:
a² + b² = c²
a = 8 millimetres
b = 15 millilitres
c = ?
8² + 15² = c²
64 + 225 = c²
64 + 225 = 289.
289 = c²
√289 = c
√289 = 17.
the pythagoras theorem correctly identified the length of the hypothenuse. as i said earlier, this theorem only works on right angled triangles, therefore, this triangle is right angled.
