Answer:
![\boxed{2^{\frac{802}{27}} \cdot 3^9}](https://tex.z-dn.net/?f=%5Cboxed%7B2%5E%7B%5Cfrac%7B802%7D%7B27%7D%7D%20%5Ccdot%203%5E9%7D)
Step-by-step explanation:
<u>I will try to give as many details as possible. </u>
First of all, I just would like to say:
![\text{Use } \LaTeX !](https://tex.z-dn.net/?f=%5Ctext%7BUse%20%7D%20%5CLaTeX%20%21)
Texting in Latex is much more clear and depending on the question, just writing down without it may be confusing or ambiguous. Be together with Latex! (*^U^)人(≧V≦*)/
![$(3^{-2} \cdot 4^{-5} \cdot 5^0)^{-3} \cdot (4^{-\frac{4}{3^3} })\cdot 3^3$](https://tex.z-dn.net/?f=%24%283%5E%7B-2%7D%20%5Ccdot%204%5E%7B-5%7D%20%5Ccdot%205%5E0%29%5E%7B-3%7D%20%5Ccdot%20%284%5E%7B-%5Cfrac%7B4%7D%7B3%5E3%7D%20%7D%29%5Ccdot%203%5E3%24)
Note that
![\boxed{a^{-b} = \dfrac{1}{a^b}, a\neq 0 }](https://tex.z-dn.net/?f=%5Cboxed%7Ba%5E%7B-b%7D%20%3D%20%5Cdfrac%7B1%7D%7Ba%5Eb%7D%2C%20a%5Cneq%200%20%7D)
The denominator can't be 0 because it would be undefined.
So, we can solve the expression inside both parentheses.
![\left(\dfrac{1}{3^2} \cdot \dfrac{1}{4^5} \cdot 5^0 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{3^3} } }\right)\cdot 3^3](https://tex.z-dn.net/?f=%5Cleft%28%5Cdfrac%7B1%7D%7B3%5E2%7D%20%20%5Ccdot%20%5Cdfrac%7B1%7D%7B4%5E5%7D%20%20%5Ccdot%205%5E0%20%5Cright%29%5E%7B-3%7D%20%5Ccdot%20%5Cleft%28%5Cdfrac%7B1%7D%7B4%5E%7B%5Cfrac%7B4%7D%7B3%5E3%7D%20%7D%20%7D%5Cright%29%5Ccdot%203%5E3)
Also,
![\boxed{a^{0} = 1, a\neq 0 }](https://tex.z-dn.net/?f=%5Cboxed%7Ba%5E%7B0%7D%20%3D%201%2C%20a%5Cneq%200%20%7D)
![\left(\dfrac{1}{9} \cdot \dfrac{1}{1024} \cdot 1 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27](https://tex.z-dn.net/?f=%5Cleft%28%5Cdfrac%7B1%7D%7B9%7D%20%20%5Ccdot%20%5Cdfrac%7B1%7D%7B1024%7D%20%20%5Ccdot%201%20%5Cright%29%5E%7B-3%7D%20%5Ccdot%20%5Cleft%28%5Cdfrac%7B1%7D%7B4%5E%7B%5Cfrac%7B4%7D%7B27%7D%20%7D%20%7D%5Cright%29%5Ccdot%2027)
Note
![\boxed{\dfrac{1}{a} \cdot \dfrac{1}{b}= \frac{1}{ab} , a, b \neq 0}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cdfrac%7B1%7D%7Ba%7D%20%5Ccdot%20%5Cdfrac%7B1%7D%7Bb%7D%3D%20%5Cfrac%7B1%7D%7Bab%7D%20%2C%20a%2C%20b%20%5Cneq%20%200%7D)
![\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27](https://tex.z-dn.net/?f=%5Cleft%28%5Cdfrac%7B1%7D%7B9216%7D%20%20%20%5Cright%29%5E%7B-3%7D%20%5Ccdot%20%5Cleft%28%5Cdfrac%7B1%7D%7B4%5E%7B%5Cfrac%7B4%7D%7B27%7D%20%7D%20%7D%5Cright%29%5Ccdot%2027)
![\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)](https://tex.z-dn.net/?f=%5Cleft%28%5Cdfrac%7B1%7D%7B9216%7D%20%20%20%5Cright%29%5E%7B-3%7D%20%5Ccdot%20%5Cleft%28%5Cdfrac%7B27%7D%7B4%5E%7B%5Cfrac%7B4%7D%7B27%7D%20%7D%20%7D%5Cright%29)
![\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)](https://tex.z-dn.net/?f=%5Cleft%28%20%5Cdfrac%7B1%7D%7B%5Cleft%28%5Cdfrac%7B1%7D%7B9216%7D%5Cright%29%5E3%7D%20%5Cright%29%5Ccdot%20%5Cleft%28%5Cdfrac%7B27%7D%7B4%5E%7B%5Cfrac%7B4%7D%7B9%7D%20%7D%20%7D%5Cright%29)
![\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)](https://tex.z-dn.net/?f=%5Cleft%28%20%5Cdfrac%7B1%7D%7B%5Cleft%28%5Cdfrac%7B1%7D%7B9216%7D%5Cright%29%5E3%7D%20%5Cright%29%5Ccdot%20%5Cleft%28%5Cdfrac%7B27%7D%7B4%5E%7B%5Cfrac%7B4%7D%7B27%7D%20%7D%20%7D%5Cright%29)
Note
![\boxed{\dfrac{1}{\dfrac{1}{a} } = a}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cdfrac%7B1%7D%7B%5Cdfrac%7B1%7D%7Ba%7D%20%7D%20%20%3D%20a%7D)
![9216^3\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)](https://tex.z-dn.net/?f=9216%5E3%5Ccdot%20%5Cleft%28%5Cdfrac%7B27%7D%7B4%5E%7B%5Cfrac%7B4%7D%7B9%7D%20%7D%20%7D%5Cright%29)
![\left(\dfrac{ 9216^3\cdot 27}{4^{\frac{4}{27} } }\right)](https://tex.z-dn.net/?f=%5Cleft%28%5Cdfrac%7B%209216%5E3%5Ccdot%2027%7D%7B4%5E%7B%5Cfrac%7B4%7D%7B27%7D%20%7D%20%7D%5Cright%29)
Once
![9216=2^{10}\cdot 3^2 \implies 9216^3=2^{30}\cdot 3^6](https://tex.z-dn.net/?f=9216%3D2%5E%7B10%7D%5Ccdot%203%5E2%20%5Cimplies%20%209216%5E3%3D2%5E%7B30%7D%5Ccdot%203%5E6)
![\boxed{(a \cdot b)^n=a^n \cdot b^n}](https://tex.z-dn.net/?f=%5Cboxed%7B%28a%20%5Ccdot%20b%29%5En%3Da%5En%20%5Ccdot%20b%5En%7D)
And
![$4^{\frac{4}{27}} = 2^{\frac{8}{27} $](https://tex.z-dn.net/?f=%244%5E%7B%5Cfrac%7B4%7D%7B27%7D%7D%20%3D%202%5E%7B%5Cfrac%7B8%7D%7B27%7D%20%24)
We have
![\left(\dfrac{ 2^{30} \cdot 3^6\cdot 27}{2^{\frac{8}{27} } }\right)](https://tex.z-dn.net/?f=%5Cleft%28%5Cdfrac%7B%202%5E%7B30%7D%20%5Ccdot%203%5E6%5Ccdot%2027%7D%7B2%5E%7B%5Cfrac%7B8%7D%7B27%7D%20%7D%20%7D%5Cright%29)
Also, once
![\boxed{\dfrac{c^a}{c^b}=c^{a-b}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cdfrac%7Bc%5Ea%7D%7Bc%5Eb%7D%3Dc%5E%7Ba-b%7D%7D)
![2^{30-\frac{8}{27}} \cdot 3^6\cdot 27](https://tex.z-dn.net/?f=2%5E%7B30-%5Cfrac%7B8%7D%7B27%7D%7D%20%5Ccdot%203%5E6%5Ccdot%2027)
As
![30-\dfrac{8}{27} = \dfrac{30 \cdot 27}{27}-\dfrac{8}{27} =\dfrac{802}{27}](https://tex.z-dn.net/?f=30-%5Cdfrac%7B8%7D%7B27%7D%20%3D%20%5Cdfrac%7B30%20%5Ccdot%2027%7D%7B27%7D-%5Cdfrac%7B8%7D%7B27%7D%20%20%3D%5Cdfrac%7B802%7D%7B27%7D)
![2^{30-\frac{8}{27}} \cdot 3^6\cdot 27 = 2^{\frac{802}{27}} \cdot 3^6 \cdot 3^3](https://tex.z-dn.net/?f=2%5E%7B30-%5Cfrac%7B8%7D%7B27%7D%7D%20%5Ccdot%203%5E6%5Ccdot%2027%20%3D%202%5E%7B%5Cfrac%7B802%7D%7B27%7D%7D%20%5Ccdot%203%5E6%20%5Ccdot%203%5E3)
![2^{\frac{802}{27}} \cdot 3^9](https://tex.z-dn.net/?f=2%5E%7B%5Cfrac%7B802%7D%7B27%7D%7D%20%5Ccdot%203%5E9)
Answer:
20.2
Step-by-step explanation:
181.1 divided by the amount of days Susie ran.
Answer:
p2q2 will give 100 as answer.
Step-by-step explanation:
Given equation can be written as:
=p^2 * q^2
by putting p=-2 and q = 5
= (-2)^2 * 5^2
As squaring the negative term vanishes the "-" So:
= 4 * 25
=100 answer
I hope it will help you!
C 1 over 2 (16 x 6) = 48 square feet.
hope this helps!
-5=-n
-5/-1 =-n/-1
5=n or n=5
This only has only solution because the n is not being squared.