I think you meant y = x^2 + 1. Please use " ^ " to denote exponentiation.
Since you haven't shared the table, I'll choose a few x values and find the corresponding y-values:
x y
-- --
0 1
1 2
2 5
10 101
The expression \[b^{-3\2} , b>0 \] is the equivalent to;
=1/b3/2=1/b3−−√
Answer:
10x^3+3y^3+11x^2-1
Step-by-step explanation:
Add common terms x and y together
10x^3+3y^3+11x^2-1
Answer:
B
Step-by-step explanation:
Answer:
If you end up with the exact opposite of what you started with (that is, if f (–x) = –f (x), so all of the signs are switched), then the function is odd.
Step-by-step explanation:
