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4 years ago

Calculate the amount of heat liberated (in kj) from 411 g of mercury when it cools from 88.0°c to 12.0°c.

1 answer:

5 0

You should note that the melting point of mercury is -38.83°C, while the boiling point is at 356.7°C. Then, that means that there is no latent heat involved here. We only compute for the sensible heat.

ΔH = mCpΔT
The Cp of mercury is 0.14 J/g·°C
Thus,
ΔH = (411 g)(0.14 J/g·°C)(88 - 12°C)
<em>ΔH = 4,373.04 J</em>

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Two charged particles are a distance of 1.72 m from each other. One of the particles has a charge of 8.08 nC, and the other has

Dmitry_Shevchenko [17]

The magnitude (in N) of the electric force that one particle exerts on the other is A. F=107.6nN.

F=[(9×10^9) ×(7.10×10^-9) ×(4.42×10^-9)] /(1.62^2)

F=(282.4×10^-9)/2.6244

F=107.6×10^-9N

F=107.6nN

Experiments with electric charges have shown that two charged objects exert electrical forces on each other. The magnitude of the force is linearly proportional to the net charge of each object and inversely proportional to the square of the distance between the objects.

Coulomb's law for calculating electrostatic forces. This force arises from the interaction between two charged objects (or point charges), the magnitude of which is calculated by F = kQ1Q2r2 F = k Q 1 Q 2 r2.

Learn more about the electric field here: brainly.com/question/14372859

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2 years ago

Something has a mass of 40 kg and a velocity of 1 m/s

lesantik [10]

m=40kg
v=1m/s

$\\ \sf\Rrightarrow K.E=\dfrac{1}{2}mv^2$

$\\ \sf\Rrightarrow K.E=\dfrac{1}{2}(40)(1)^2$

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m=80kg

$\\ \sf\Rrightarrow K.E=\dfrac{1}{2}(80)(1)^2$

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3 years ago

A 650 kg steel beam is being pulled up by a crane with a force of 7020 N. What is the upwards acceleration of the beam?

zimovet [89]

Answer: 1 m/s^2

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3 years ago

Which would fall with greater acceleration in a vacuum a leaf or a stone?

Sergeu [11.5K]

Because its a vacuum, there's no air resistance, they will fall at same time
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3 0

3 years ago

Read 2 more answers

a flashlight bulb with a potential difference of 6.0 v across it has a resistance of 8.0 how much current is the bulb filament

Andreas93 [3]

Answer:

Explanation:

Ohm's law states that the current (I) through a conductor between two points is directly proportional to the voltage (V) across the two points. The constant of proportionality is called the Resistance (R) of the conductor.

The formula can be expressed as:

V = I.R

The intensity of the current through a resistor can be calculated by solving the equation for I:

$\displaystyle I=\frac{V}{R}$

A flashlight bulb is an example of a resistor with the specific task to emit light when it's hot enough.

The potential difference (or voltage) is V=6 V and the resistance is R=8Ω, thus the current is:

$\displaystyle I=\frac{6~V}{8~\Omega}$

I = 0.75 Amp

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3 years ago