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mina [271]
3 years ago
5

Calculate the amount of heat liberated (in kj) from 411 g of mercury when it cools from 88.0°c to 12.0°c.

Physics
1 answer:
Katen [24]3 years ago
5 0
You should note that the melting point of mercury is -38.83°C, while the boiling point is at 356.7°C. Then, that means that there is no latent heat involved here. We only compute for the sensible heat.

ΔH = mCpΔT
The Cp of mercury is 0.14 J/g·°C
Thus,
ΔH = (411 g)(0.14 J/g·°C)(88 - 12°C)
<em>ΔH = 4,373.04 J</em>
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Answer:

0.5A

Explanation:

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2 years ago
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3 years ago
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Explanation:

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here we know that

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now we have

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6 0
3 years ago
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3 years ago
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Anna71 [15]

Answer:

The unknown frequency is either 438 Hz or 442 Hz.

Explanation:

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The unknown frequency is either 438 Hz or 442 Hz.

Hope this Helps!!!

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