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natita [175]
3 years ago
9

to what temperature it will a 30 KG of glass raise if it absorbs 4275 joules of heat in its specific heat is 0.5 J/KG degree cel

sius. The initial temperature of the glass is 35°C
Physics
1 answer:
natima [27]3 years ago
7 0

Answer:

230° C

Explanation:

A substance's specific heat tells you how much heat much either be added or removed from 1 g of that substance in order to cause a 1∘C

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The shape of a liquid can change because the atoms in it are not close together to form a solid, they flow freely.
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Describes the relationship between the free energy change, the reaction quotient, and the equilibrium constant.
LUCKY_DIMON [66]

<u>Explanation:</u>

Reaction quotient is defined as the ratio of the concentration of the products and reactants of a reaction at any point of time with respect to some unit. It is represented by the symbol <em>Q</em>.

The ratio of the concentration of products and reactants of a reaction in equilibrium with respect to some unit is said to be equilibrium constant expression. It is represented by the symbol <em>K</em>.

The relationship between Gibbs free energy change and reaction quotient of the reaction is:

\Delta G=\Delta G^o+RT ln Q           ......(1)

where,

\Delta G = Gibbs free energy change

\Delta G^o = Standard Gibbs free energy change

R = Gas constant

T = Temperature

At equilibrium, the free energy change of the reaction becomes 0 and standard Gibbs free energy change can be related to the equilibrium constant by the equation:

\Delta G^o=-RT ln Q           ...(2)

4 0
3 years ago
After the driver first notices the obstacle, the car moves uniformly for a time interval t1−t0=t before the brakes are applied.
loris [4]

Answer:

V(t1-t0)

Explanation:

Moving 'uniformly' means constant velocity (speed). the formula for constant speed motion is V = \frac{distance}{time} =( change in position/ change in time)

where,

                  V is speed

given in the statement :

change in time = t =  t1-t0

let the constant speed be ' V '

disance = X = X1-X0

applying the above mentioned formula: V = \frac{X}{t}

V = X/t

X = Vt

the distance X1-X0 = Vt =V(t1-t0)

3 0
3 years ago
A girl stands on the edge of a merry-go-round of radius 1.71 m. If the merry go round uniformly accerlerates from rest to 20 rpm
Mashutka [201]

Answer:

a = 0.53 m/s^2

Explanation:

initially the merry go round is at rest

after 6.73 s the merry go round will accelerates to 20 rpm

so final angular speed is given as

\omega = 2\pi f

\omega = 2\pi ( \frac{20}{60})

\omega = 2.10 rad/s

so final tangential speed is given as

v = r\omega

v = 1.71 (2.10) = 3.58 m/s

now average acceleration of the girl is given as

a = \frac{v_f - v_i}{\Delta t}

a = \frac{3.58 - 0}{6.73}

a = 0.53 m/s^2

8 0
3 years ago
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